Question

我有一段代码可以读取SQL数据并将其转换为JSON格式

$sql = "SELECT students.studentnumber, students.firstname, students.lastname, badge_id FROM students
  INNER JOIN student_has_badge
WHERE student_has_badge.badge_id = 10
  AND student.studentnumber = student_has_badge.studentnumber
ORDER BY lastname ASC
LIMIT 50;";

$result = mysqli_query($connection, $sql) or die("Error in Selecting " . mysqli_error($connection));

//creating an array
$emparray = array();
while ($row = mysqli_fetch_assoc($result)) {
  $emparray[] = $row;
}

echo json_encode($emparray);
mysqli_close($connection);

我从中获得的输出如下所示：

[{"studentnumber":"11111","firstname":"John","lastname":"Smith","badge_id":"10"},
{"studentnumber":"1","firstname":"Nick","lastname":"Smith","badge_id":"10"},
{"studentnumber":"500740442","firstname":"Jason","lastname":"Baker","badge_id":"10"},
{"studentnumber":"00000","firstname":"Tim","lastname":"Smith","badge_id":"10"}]

现在我想把这些数据放在一个HTML表格中，我尝试了各种各样的方法，但是没有它们有效，有人能指出我正确的方向吗？

Answer 1

<?php
$emparray ='[{"studentnumber":"11111","firstname":"John","lastname":"Smith","badge_id":"10"},{"studentnumber":"1","firstname":"Nick","lastname":"Smith","badge_id":"10"},{"studentnumber":"500740442","firstname":"Jason","lastname":"Baker","badge_id":"10"},"studentnumber":"00000","firstname":"Tim","lastname":"Smith","badge_id":"10"}]';

$emparray = json_decode($emparray,1);
echo '<table border="1"><tr><th>Student#<th>First name</th><th>lastname</th><th>badge id</th></tr>';
foreach($emparray as $key => $value){
     echo '<tr><td>'.$value['studentnumber'] . '</td><td>'.$value['firstname'] . '</td><td>'.$value['lastname'] . '</td><td>'.$value['badge_id'] .'</td></tr>';
}
echo '</table>';
?>

Answer 2

如果你想要一个PHP解决方案，那么你不需要JSON数据，只需从原始数组创建一个表。

<?php
echo '<table id="emparray"><tr>'
    .'<th class="studentnumber">Student Number</th>'
    .'<th class="firstname">First name</th>'
    .'<th class="lastname">Last name</th>'
    .'<th class="badge_id">Badge ID</th>'
    .'</tr>';
foreach ($emparray as $e) {
    echo '<tr><td class="studentnumber">'.$e['studentnumber'].'</td>'
        .'<td class="firstname">'.$e['firstname'].'</td>'
        .'<td class="lastname">'.$e['lastname'].'</td>'
        .'<td class="badge_id">'.$e['badge_id'].'</td></tr>';
}
echo '</table>';
?>

JSON格式到HTML表格

2 个答案: