Question

我有下一个代码：

ind=[{'id':123,'name'='Andrew','universities':[{'country'=123,'state'=123}], school=[{'name'=Beliech,'state'=...}],'type'=[{}] }]

我需要在学校领域取名学校的名称，并在大学领域与国家说明将其添加到数据库中。我试图将list ind转换为字典（info = ind [0]），然后获取信息，但我遇到了问题，该学校也是一个列表，所以我不能使用ind['school']['name']。大学和学校不是一成不变的，它们可以相互替代，并保持在开始/结束/中间。我该如何获取此信息？

Answer 1

import pandas
ind=[{'id':123,'name':'Andrew','universities':[{'country':123,'state':1234}], 'school':[{'name':"Beliech"}]}]
name_list = []
school_name_list = []
university_country_list = []
university_state_list = []
for i in range(len(ind)):
    name_list.append(ind[i]['name'])
    school_name_list.append(ind[i]['school'][0]['name'])
    university_country_list.append(ind[i]['universities'][0]['country'])
    university_state_list.append(ind[i]['universities'][0]['state'])
Output = pandas.DataFrame({'Name':name_list,'School_Name':school_name_list,'University_Country':university_country_list,'University_State':university_state_list})

我对这个问题并不十分清楚。根据我的理解，这就是我能想到的

Answer 2

我试着回答你，但实际上我无法理解一些观点。

ind = [{'id':123, 'name':'Andrew','universities':[{'country':123,'state':123}], 'school':[{'name':'Beliech','state':...}],'type':[{}]}]

list_dict = []
for index in range (0, len(ind[0]["school"])):
    new_dict = {
        "School_Name" :  ind[0]["school"][index]["name"],
        "University_Country": ind[0]["universities"][index]["country"],
        "University_State": ind[0]["universities"][index]["state"],
    }
    list_dict.append(new_dict)

我只是为每个学校创建一个字典，大学与之相关联。在您的示例中，Beliech学校与国家123和州123中的大学相关联。所有词典都存储在列表中。我不知道这是不是你真正想要的。我希望如此。

请注意字典键。你把学校和Beliech写成两个变量而不是字符串。我认为这不是你想要的。

修改

我希望这将是你正在寻找的。如果没有，请尝试更准确，请：

ind = [{'id':123, 'name':'Andrew','universities':[{'country':123,'state':123}], 'school':[{'name':'Beliech','state':...}],'type':[{}]}] user_name = input("Please, enter your name") for index in range (0, len(ind)): if ind[index]["name"] == user_name: dict = ind[index] school_list = [] for school in range(0, len(dict["school"])): school_list.append(dict["school"][school]["name"]) university_list = [] # list of dictionary with all the info about a University universitycountry_list = [] universitystate_list = [] for uni in range(0, len(dict["universities"])): university_list.append(dict["universities"][uni]) universitycountry_list.append(dict["universities"][uni]["country"]) universitystate_list.append(dict["universities"][uni]["state"]) found = True break else: found = False if not found: print("The user {} is not in the Database".format(user_name)) # print(school_list) # print(university_list) # print(universitycountry_list) # print(universitystate_list)

从字典中的列表中获取信息

2 个答案: