Question

从sqlite获取长字符串时遇到错误。在sqlite中存储长字符串是否有任何限制。我面临以下错误

 Couldn't read row 0, col 0 from CursorWindow.  Make sure the Cursor is initialized correctly before accessing data from it.

这是我的创建表查询

 private static final String CREATE_TABLE2 = "create table " + SHAREDPREFERANCEVIDEO_TABLE + " ( ID INTEGER PRIMARY KEY AUTOINCREMENT,"+
        "storedvalue1 TEXT)";

这里是获取单行的功能，这只是我表中的一行

  public String sharedprefindb (int position) {

    String value="";
    String id =Integer.toString(position);
    SQLiteDatabase db =this.getReadableDatabase();
    Cursor cursor = db.rawQuery("SELECT  *  FROM "+ " sharedpreferancevideo_talbe " + " WHERE ID = ? ", new String[] {id});;
    if(cursor.getCount()!=0)
    {
        if(cursor.moveToFirst()){
            do{
                value=cursor.getString(cursor.getColumnIndex("storedvalue1"));
            }while(cursor.moveToNext());
        }
        cursor.close();
    }
    return value;
}

我的这段代码在另一个字符串非常小的项目中工作正常但在这段代码中，我存储了加密数据，因此其文本非常长。所以任何想法我在哪里做错了。

Answer 1

<强>更新通过更改您的功能来尝试此解决方案：

public String sharedprefindb (int position) {

    String value="";
    String id =String.valueOf(position);
    SQLiteDatabase db =this.getReadableDatabase();
    Cursor cursor = db.rawQuery("SELECT  *  FROM "+ " sharedpreferancevideo_talbe " + " WHERE ID = '"+position+"'", null);;
    if(cursor!=null && cursor.getCount() > 0)
    {
        if(cursor.moveToFirst()){
            do{
                value=cursor.getString(cursor.getColumnIndex(1));
            }while(cursor.moveToNext());
        }
    }
    cursor.close();
    return value;
}

从mysqlite获取单行时获取游标错误

1 个答案: