我的数据是这样的:
| visitor_id | time | my_flag |
| 1 | 01-01-2017 | 1 |
| 2 | 01-01-2017 | 1 |
| 1 | 01-02-2017 | 2 |
| 3 | 01-02-2017 | 2 |
等...
我希望在一天内对所有访客进行分组,但会根据标记进行分组。标志可以有两个值,1或2.所以我需要像
这样的东西| 12 | 01-01-2017 | 1 |
| 10 | 01-01-2017 | 2 |
| 34 | 01-02-2017 | 1 |
我有
select v.visitor_id v.time, v.flag
from my_table as v
group by DAY(v.time) having flag=1;
但我无法弄清楚如何添加多个条件(flag = 1和flag = 2)?有什么指针吗?
答案 0 :(得分:1)
尝试这样的事情
select v.visitor_id v.time, v.flag
from my_table as v
where v.flag in (1,2)
group by DAY(v.time), v.flag
答案 1 :(得分:1)
SELECT v.time,
v.flag,
COUNT(v.visitor_id)
FROM my_table as v
GROUP BY v.time,
v.flag;`