Question

string = "The is a better :: sentence as :: compared to that"

输出：

更好的句子
相比

我尝试了以下内容，

string.split(" :: "), 
re.sub("[\<].*?[\>]", "", string)

这些不会给我特定的话

Answer 1

>>> string = "The is a better :: sentence as :: compared to that" 
>>> x = [' '.join(x) for x in map(lambda x: (x[0].split()[-1], x[1].split()[0]), zip(string.split('::')[:-1], string.split('::')[1:]))]
>>> x

输出：

['better sentence', 'as compared']

Disection：

首先，基于::和zip组连续匹配进行拆分

pairs = zip(string.split('::')[:-1], string.split('::')[1:]))

如果你list()那个表达式，你得到：

[('The is a better ', ' sentence as '), (' sentence as ', ' compared to that')]

接下来，应用一个函数从第一个元素中提取最后一个单词，从第二个元素中提取每个元组的第一个单词：

new_pairs = map(lambda x: (x[0].split()[-1], x[1].split()[0]), pairs)

如果你list()那个表达式，你得到：

[('better', 'sentence'), ('as', 'compared')]

最后，在列表解析中加入每个元组：

result = [' '.join(x) for x in new_pairs]

输出：

['better sentence', 'as compared']

timeit结果：

The slowest run took 4.92 times longer than the fastest. This could mean that an intermediate result is being cached.
100000 loops, best of 3: 5.74 µs per loop

这是re的另一种方式。

import re
string = "The is a better :: sentence as :: compared to that" 
result = [' '.join(x) for x in re.findall('([\w]+) :: ([\w]+)', string)]

输出：

['better sentence', 'as compared']

timeit结果：

The slowest run took 4.60 times longer than the fastest. This could mean that an intermediate result is being cached.
100000 loops, best of 3: 4.49 µs per loop

Answer 2

使用re.findall()函数的解决方案：

s = "The is a better :: sentence as :: compared to that"
result = [' '.join(i) for i in re.findall(r'(\w+) ?:: ?(\w+)', s)]

print(result)

输出：

['better sentence', 'as compared']

Answer 3

这是另一种方式：

1st）获取分隔符的索引

indices = [idx for idx, elem in enumerate(string.split(' ')) if elem == '::']

2）加入分隔符周围的单词

for idx in indices:
    print ' '.join(string.split(' ')[idx-1:idx+2:2])

'better sentence'
'as compared'

在分隔符之前和之后查找单词

3 个答案: