Question

我有一个名为“Sentence varchar（100）”的专栏它包含数据

"first name, last name : is Activated on 01/01/2017 "
"first name, last name : is Downloaded on 01/01/2017 "
"first name, last name : is Deleted on 01/01/2017 "
"first name, last name : is Deactivated on 01/01/
"first name, last name : is Born on 01/01/2017 "

这里我想要一个sql查询来显示每个字符串为 “名字，姓氏：已激活” “名字，姓氏：出生”

我想从“on the ...... so”中删除字符串

你能帮我解决这个问题。如何为此编写一个sql server查询。

Answer 1

你很幸运，因为要删除的字符串部分是固定长度的。所以，你可以这样做：

url

＆＃34; 14＆＃34;是select left(sentence, len(sentence) - 14)的长度。

Answer 2

这不是规范化表格，因此非常难以使用。

你应该有一张像

这样的表

Event: Id | firstName | lastName | date | eventTypeId

其中EventType代表Activated，Downloaded，Deleted，代表2列：

EventType: Id | eventName

然后，您可以通过以下方式重建数据：

SELECT CONCAT(firstName," , ",lastName," : is ",EventType.eventName," on ",date) 
    FROM EVENT
    JOIN EventType ON EventType.id=Event.eventTypeId

或者，要获取没有日期的数据：

SELECT CONCAT(firstName," , ",lastName," : is ",EventType.eventName) 
    FROM EVENT
    JOIN EventType ON EventType.id=Event.eventTypeId

Answer 3

您可以使用替换

EVENT_TRACE_REAL_TIME_MODE

Answer 4

类似于：UPDATE Table SET Sentence = SUBSTR(Sentence, 0, LOCATE(' on ', Sentence))

Answer 5

这是一个有效的解决方案。

-- Sample data
DECLARE @yourdata TABLE (sentence varchar(100));
INSERT @yourdata VALUES 

('first name, last name : is Activated on 01/01/2017'),
('first name, last name : is Downloaded on 01/01/2017'),
('first name, last name : is Deleted on 01/01/2017'),
('first name, last name : is Deactivated on 01/01/'),
('first name, last name : is Born on 01/01/2017');

--Solution
SELECT sentenceNew = SUBSTRING(sentence, 1, PATINDEX('% on [0-9][0-9]/%', sentence)-1)
FROM @yourdata;

结果：

-----------------------------------------
first name, last name : is Activated
first name, last name : is Downloaded
first name, last name : is Deleted
first name, last name : is Deactivated
first name, last name : is Born

sql查询从varchar（100）句子中删除特定字符串

5 个答案: