Question

我有一个MysqlTime结构，它有自己的马歇尔和解组。

type MysqlTime struct {
    time.Time
}

const MYSQL_TIME_FORMAT = "2006-01-02 15:04:05"

func (t *MysqlTime) UnmarshalJSON(b []byte) (err error) {
    s := strings.Trim(string(b), `\`)
    if s == "null" {
        t.Time = time.Time{}
        return
    }
    t.Time, err = time.Parse(MYSQL_TIME_FORMAT, s)
    return
}

func (t *MysqlTime) MarshalJSON() ([]byte, error) {
    if t.Time.UnixNano() == nilTime {
        return []byte("null"), nil
    }
    return []byte(fmt.Sprintf(`"%s"`, t.Time.Format(MYSQL_TIME_FORMAT))), nil
}

var nilTime = (time.Time{}).UnixNano()

func (t *MysqlTime) IsSet() bool {
    return t.UnixNano() != nilTime
}

现在我想用它......

type Foo struct {
    Time *MysqlTime
}

func main() {

    now := MysqlTime(time.Now())

    foo := Foo{}
    foo.Time = &now
}

错误：

cannot convert now (type time.Time) to type helpers.MysqlTime
cannot take the address of helpers.MysqlTime(now)

Answer 1

这样做时：

now := MysqlTime(time.Now())

它会尝试将Time转换为您的MysqlTime类型（会引发错误）。

您是否真的要初始化内部Time属性，就像这样？

now := MysqlTime{time.Now()}

自定义时间Marshall Unmarshall

1 个答案: