grep - 按匹配的单词分组

Question

假设我有一个带例外的日志文件：

NoReceiveTaskException
NullPointerException
InvalidArgumentException
etc

如何按匹配的单词分组grep，以便每个Exception在结果中只出现一次？

示例输出：

grep Exception error.log

Caused by: java.lang.NullPointerException
Caused by: java.lang.NullPointerException
Caused by: java.lang.NullPointerException
doInTransaction       190 | NoReceiveTaskException
doInTransaction       190 | NoReceiveTaskException
doInTransaction       190 | NoReceiveTaskException

Answer 1

您也可以使用awk

awk '/Exception/{l[$0]}END{for(e in l){print e}}' error.log