这些是我目前的数据
ACCOUNT NUMBER PRODUCT STATUS RANK DESIGN
1 530033 Wealth Services Closed 1 Manual
2 530033 Wealth Services Closed 2 Manual
3 530033 Wealth Services Closed 3 Manual
4 530033 Wealth Services Closed 4 Manual
5 534656 Initial Escrow Open 1 Manual
6 534656 Initial Escrow Open 2 Manual
7 535161 Markets Integrity Closed 1 Manual
8 538379 Prepaid Cards Closed 1 Manual
9 538379 Prepaid Cards Closed 2 Manual
10 538379 Prepaid Cards Closed 3 Manual
11 538379 Prepaid Cards Closed 4 Manual
12 538915 Uploaded Cards Open 1 Manual
13 538915 Uploaded Cards Open 2 Manual
14 538915 Uploaded Cards Open 3 Manual
我想创建一个唯一计算每个重复帐号的列。例如帐号530033出现了四次，我想将每个530033计为一个，与其他帐号534656一样出现两次直到被计为一个。
我已经尝试过以下操作，但这些都不起作用。
count(distinct(Account Number))
count(distinct(Account Number) for Account Number)
使用Aggregate列等于TOTAL，COUNT或AUTOMATIC。
我将使用数据创建交叉表。我的交叉表给了我一个14的总计数，因为它计算了所有重复的帐号。因为所有帐号都有十四行。但实际上只有5个帐号（530033,534656,535161,538379和53891）
TOTAL Open Closed
Wealth Services 4 4
Initial Escrow 2 2
Markets Integrity 1 1
Prepaid Cards 4 4
Uploaded Cards 3 3
TOTAL 14
理想情况下应该是这样的。
TOTAL Open Closed
Wealth Services 1 1
Initial Escrow 1 1
Markets Integrity 1 1
Prepaid Cards 1 1
Uploaded Cards 1 1
TOTAL 5
我应该创建一个名为唯一帐号的新列吗？但我如何单独计算帐号？
我是否必须创建另一个具有唯一帐号的表，然后在内部加入两个表？
答案 0 :(得分：1)
我相信你需要的表达方式如下：
TOTAL
COUNT(DISTINCT [ACCOUNT NUMBER] for [PRODUCT])
打开
CASE [STATUS]
WHEN 'Open' THEN COUNT(DISTINCT [ACCOUNT NUMBER] for [PRODUCT],[STATUS])
ELSE NULL
END
<强>闭
CASE [STATUS]
WHEN 'Closed' THEN COUNT(DISTINCT [ACCOUNT NUMBER] for [PRODUCT],[STATUS])
ELSE NULL
END
确保将每个数据项的聚合函数设置为“已计算”，因为我们手动指定聚合和汇总。