当列名包含空格时,dplyr :: mutate_if会失败

时间:2017-06-27 13:20:30

标签: r dplyr

我有以下情况:我有一个tibble和一个字符向量,它包含了一些所说的tibbles列名。现在我使用dplyr::mutate_if将这些列设置为0,其名称包含在字符向量中。我这样做是通过提供一个逻辑向量作为谓词。

到目前为止,这已经奏效了:

library(tidyverse)

test_OK <-
  tribble(~"Var1", ~"Var2", ~"Var3",
          11,      12,      13,
          21,      22,      23,
          31,      32,      33)

vars_to_change_OK <- c("Var1", "Var3")

## Everything works out
test_OK %>% mutate_if(names(.) %in% vars_to_change_OK, funs(. * 0))

但是现在我在列名中出现了空格和数字,并且程序失败了:

test_FAIL <-
  tribble(~"Var 1", ~"Var 2", ~"Var 3",
            11,      12,      13,
            21,      22,      23,
            31,      32,      33)

vars_to_change_FAIL <- c("Var 1", "Var 3")

## Error [...] unexpected numeric constant
test_FAIL %>% mutate_if(names(.) %in% vars_to_change_FAIL, funs(. * 0))

请注意,唯一的区别是从Var[0-9]更改为Var [0-9]的列名称。

我想知道这是dplyr中的错误,还是我以非预期的方式使用mutate_if功能。此外,我对错误发生的方式和原因感兴趣。提前感谢任何见解!

PS:我知道有一个简单的基础R解决方法,如下所示:

###############################
## workaround in base R:
test_FAIL[, match(vars_to_change_FAIL, names(test_FAIL))] <- 0
test_FAIL

然而,我对上述为什么在dplyr中不起作用感兴趣。

更新:我已添加sessionInfo(),以防版本重要:

R version 3.4.0 (2017-04-21)
Platform: x86_64-w64-mingw32/x64 (64-bit)
Running under: Windows >= 8 x64 (build 9200)

Matrix products: default

locale:
[1] LC_COLLATE=German_Germany.1252  LC_CTYPE=German_Germany.1252    LC_MONETARY=German_Germany.1252
[4] LC_NUMERIC=C                    LC_TIME=German_Germany.1252    

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods   base     

other attached packages:
 [1] dplyr_0.5.0          purrr_0.2.2          readr_1.1.0          tidyr_0.6.1          tibble_1.3.0        
 [6] ggplot2_2.2.1        tidyverse_1.1.1      dygraphs_1.1.1.4     shiny_1.0.3          RevoUtilsMath_10.0.0

loaded via a namespace (and not attached):
 [1] Rcpp_0.12.10     cellranger_1.1.0 compiler_3.4.0   plyr_1.8.4       forcats_0.2.0    tools_3.4.0      digest_0.6.12   
 [8] lubridate_1.6.0  jsonlite_1.4     nlme_3.1-131     gtable_0.2.0     lattice_0.20-35  psych_1.7.3.21   DBI_0.6-1       
[15] parallel_3.4.0   haven_1.0.0      xml2_1.1.1       httr_1.2.1       stringr_1.2.0    hms_0.3          RevoUtils_10.0.4
[22] htmlwidgets_0.8  grid_3.4.0       R6_2.2.0         readxl_1.0.0     foreign_0.8-67   modelr_0.1.0     reshape2_1.4.2  
[29] magrittr_1.5     scales_0.4.1     htmltools_0.3.6  rvest_0.3.2      assertthat_0.2.0 mnormt_1.5-5     colorspace_1.3-2
[36] mime_0.5         xtable_1.8-2     httpuv_1.3.3     stringi_1.1.5    lazyeval_0.2.0   munsell_0.4.3    broom_0.4.2     
[43] zoo_1.8-0       

1 个答案:

答案 0 :(得分:3)

我们可以使用mutate_at并将'vars_to_change_FAIL'放在vars

test_FAIL %>% 
      mutate_at(vars(vars_to_change_FAIL), funs(. * 0))
#  A tibble: 3 x 3
#   `Var 1` `Var 2` `Var 3`
#    <dbl>   <dbl>   <dbl>
#1       0      12       0
#2       0      22       0
#3       0      32       0