将DateTime转换为整数

Question

我试图将今天的日期作为整数返回。我试图将它作为字符串返回，它工作正常。但是如何将其作为整数返回？

public string ConvertInvoiceDate()
{
    return DateTime.Today.ToString("yyyyMMdd");
}

整数应与yyyyMMdd的格式相同。返回类型是字符串，因为我正在尝试使用字符串。现在我不确定我是否必须返回long / double。使用BizTalk我试图将a值插入Oracle DB中的字段，其类型为Numeric。当我尝试以字符串形式返回时，它会将错误抛出为The value for field "INVOICE_DTE" is invalid. ---> System.FormatException: The string '20170626' is not a valid AllXsd value.

DB中字段的详细信息在

之下

完整的错误消息是

A message sent to adapter "WCF-Custom" on send port "WcfSendPort_OracleDBBinding_Table_MACINVOICE_Custom" with URI "oracledb://xxxxx/" is suspended. 
 Error details: Microsoft.ServiceModel.Channels.Common.XmlReaderParsingException: The value for field "INVOICE_DTE" is invalid. ---> System.FormatException: The string '20170626' is not a valid AllXsd value.
   at System.Xml.Schema.XsdDateTime..ctor(String text, XsdDateTimeFlags kinds)
   at System.Xml.XmlConvert.ToDateTime(String s, XmlDateTimeSerializationMode dateTimeOption)
   at Microsoft.Adapters.OracleCommon.OracleCommonMetadataUtils.ConvertXmlToLob(String text, XmlTypeCode xmlTypeCode, QualifiedType qualifiedType, String fieldName)
   --- End of inner exception stack trace ---

Server stack trace: 
   at System.Runtime.AsyncResult.End[TAsyncResult](IAsyncResult result)
   at System.ServiceModel.Channels.ServiceChannel.SendAsyncResult.End(SendAsyncResult result)
   at System.ServiceModel.Channels.ServiceChannel.EndCall(String action, Object[] outs, IAsyncResult result)
   at System.ServiceModel.Channels.ServiceChannel.EndRequest(IAsyncResult result)

Exception rethrown at [0]: 
   at System.Runtime.Remoting.Proxies.RealProxy.HandleReturnMessage(IMessage reqMsg, IMessage retMsg)
   at System.Runtime.Remoting.Proxies.RealProxy.PrivateInvoke(MessageData& msgData, Int32 type)
   at System.ServiceModel.Channels.IRequestChannel.EndRequest(IAsyncResult result)
   at Microsoft.BizTalk.Adapter.Wcf.Runtime.WcfClient`2.RequestCallback(IAsyncResult result) 
 MessageId:  {449B56A2-B053-47A4-826A-400B97CFB9A1}
 InstanceID: {DEA7CAA7-D589-4A4E-81A0-A2C6A961D340}

Answer 1

在返回之前将它们转换为整数，如下所示：

public int ConvertInvoiceDate()
{
    return int.Parse(DateTime.Today.ToString("yyyyMMdd"));
}

Try this Example

Answer 2

正如Panagiotis Kanavos在评论中所说，XML字段可能被定义为使用ISO8601格式的xsd :: datetime，即2017-06-23T13:14:15Z

要实现这一目标，您可以执行以下操作，或者更简单地将datetime functoid连接到地图中的节点。

public string ConvertInvoiceDate()
{
    return DateTime.Today.ToString("o");
}

Answer 3

再试一次

int.Parse(DateTime.Today.ToShortDateString().Replace("-",""))

Answer 4

也许你想做这样的事情？

DateTime.Today.Ticks

是long，而不是int。 Ticks property reference

Answer 5

如果您正在寻找DateTime对象的数值，则有一个属性Ticks，但它是长类型，而不是int。

https://msdn.microsoft.com/ru-ru/library/system.datetime.ticks(v=vs.110).aspx

Answer 6

Downvote完全错了！本答案基于完全不同的问题的先前版本

HOLD ON！

不要使用字符串或整数。您需要使用TryParseExact（）返回DateTime。