Question

我想将日期（以毫秒为单位）转换为日期，但无法正确转换。

public static void main(String[] args) {        
    LocalDate today = LocalDateTime.now().toLocalDate();
    System.out.println("Today: ----------" + today);
    long todayLong = today.atStartOfDay(ZoneId.systemDefault()).toEpochSecond();
    System.out.println("todayLong: ---------- " + todayLong);
    LocalDate todayBack = Instant.ofEpochMilli(todayLong).atZone(ZoneId.systemDefault()).toLocalDate();
    System.out.println("todayBack: ---------- "+todayBack);
}

这是输出：

今天：---------- 2017-06-27

今天长：---------- 1498507200

todayBack：---------- 1970-01-18

Answer 1

您需要使用ofEpochSecond代替ofEpochMilli，因为todayLong为second，而不是milisecond

LocalDate todayBack = Instant.ofEpochSecond(todayLong).atZone(ZoneId.systemDefault()).toLocalDate();

Answer 2

你在第6行（Instant.ofEpochMilli）有一点错误。请改用Instant.ofEpochSecond：

LocalDate today = LocalDateTime.now().toLocalDate();
System.out.println("Today: ----------" + today);
long todayLong = today.atStartOfDay(ZoneId.systemDefault()).toEpochSecond();
System.out.println("todayLong: ---------- " + todayLong);
LocalDate todayBack = Instant.ofEpochSecond(todayLong).atZone(ZoneId.systemDefault()).toLocalDate();
System.out.println("todayBack: ---------- " + todayBack);

Answer 3

你必须将todayLong乘以1000

LocalDate todayBack = Instant.ofEpochMilli(todayLong * 1000).atZone(ZoneId.systemDefault()).toLocalDate();

System.out.println("todayBack: ---------- " + todayBack);

获取输出：

今天：---------- 2017-06-27

今天长：---------- 1498514400

今天回来：---------- 2017-06-27

Java 8 LocalDate从长期到今天未正确转换

3 个答案: