我多次检查了功能列表,似乎级联应该可行。 当我执行这个python脚本时:
#!/usr/bin/env python3
import sqlite3
print(sqlite3.sqlite_version)
con = sqlite3.connect(':memory:')
a = "create table a (id integer primary key, name text)"
con.execute(a)
b = "create table b (id integer primary key, r integer, foreign key(r) references a(id) on delete cascade)"
con.execute(b)
con.commit()
a = "insert into a (name) values (\"abc\")"
con.execute(a)
con.commit()
print(con.execute("select * from a").fetchall())
a = "insert into b (r) values (1)"
con.execute(a)
con.commit()
print(con.execute("select * from b").fetchall())
a = "delete from a where id=1"
con.execute(a)
con.commit()
print(con.execute("select * from b").fetchall())
print(con.execute("select * from a").fetchall())
我得到了这些结果:
3.7.4
[(1, 'abc')]
[(1, 1)]
[(1, 1)]
[]
这证明级联没有发生。我做错了什么或者得到与级联相同结果的解决方案是什么?
答案 0 :(得分:9)
出于兼容性目的,禁用SQLite外键。您需要在每次连接数据库后立即手动启用它们。
con.execute("PRAGMA foreign_keys = ON")
答案 1 :(得分:2)
用户Thibault J在这个问题上有一个更好的答案:Enable integrity checking with sqlite in django说:
from django.db.backends.signals import connection_created
def activate_foreign_keys(sender, connection, **kwargs):
"""Enable integrity constraint with sqlite."""
if connection.vendor == 'sqlite':
cursor = connection.cursor()
cursor.execute('PRAGMA foreign_keys = ON;')
connection_created.connect(activate_foreign_keys)