with temp as(select top 5 * from tblJobs) -- **select data from tblJobs**
select a.FirstName,a.LastName,a.Email ,b.City,a.Latitude,a.Longtitude
from tbljobSeeker as a --select data from tblJobSeeker
inner join tblCity as b on( b.CityID = a.CityID) -- **inner join for CityName **
inner join temp as d on d.Latitude like CONCAT('%',a.Latitude,'%' )
and d.Longtitude like CONCAT('%',a.Longtitude,'%')
-- ** inner join for top 5 jobs with basis of Latitude & Longtitude **
where CAST(a.Latitude AS DECIMAL(9,2)) BETWEEN CAST(d.Latitude AS DECIMAL(9,2))-0.10 AND CAST(d.Latitude AS DECIMAL(9,2))+0.10
and CAST(a.Longtitude AS DECIMAL(9,2)) BETWEEN CAST(d.Longtitude AS DECIMAL(9,2))-0.10 AND CAST(d.Longtitude AS DECIMAL(9,2))+0.10
and a.IsDelete = 0
我有一份工作表，其中有13个工作，我有另一个工作表求职者。 我想要求职者的电子邮件列结果。两个表的常用参数是 Latitude＆amp; varchar 中的Longtitude ，但我得到了空集，查询中出现了错误
tblJobSeeker数据
ID JobSeekerCode FirstName LastName Email Latitude Longutude
1 JS0001 Someone Example abc@xyz.com 22.494636249263564 88.37204933166504
2 JS0002 Someone1 Example1 abc1@xyz.com 19.11986822166177 73.0070686340332
3 JS0003 Someone2 Example2 abc2@xyz.com 19.20447041013782 72.8207581040624
TABLE tbljobs
ID JOBCODE EmployerCode Latitude Longutude
1 JOB0001 EMP0018 19.08580444766317 72.8364372253418
2 JOB0002 EMP0008 28.7041 77.30435371398926
3 JOB0003 EMP0022 19.162519142081003 72.83819675445557
7 JOB0006 EMP0001 19.06917553583066 72.83819675445557
8 JOB0007 EMP0001 19.130248167229208 72.84673690795898