Question

我正在使用Android创建一个Kotlin代码来创建一个检查用户名和密码的Activity。我正在使用凌空来做这件事。我在我的MainActivity中使用此功能来执行此操作：

private fun checking(){

        val name: String = editText?.text.toString()
        val password: String = editText2?.text.toString()

        val stringRequest = object : StringRequest(Request.Method.POST, 192.168.1.50,
                Response.Listener<String> {
                    response ->
                    try {
                        val obj = JSONObject(response)
                        Toast.makeText(applicationContext, obj.getString("message"), Toast.LENGTH_LONG).show()
                    } catch (e: JSONException) {
                        e.printStackTrace()
                    }
                },
                object : Response.ErrorListener {
                    override fun onErrorResponse(volleyError: VolleyError) {
                        Toast.makeText(applicationContext, volleyError.message, Toast.LENGTH_LONG).show()
                    }
                }) {
            @Throws(AuthFailureError::class)
            override fun getParams(): Map<String, String> {
                val params = HashMap<String, String>()
                params.put("name", name)
                params.put("password", password)
                return params
            }
        }
        VolleySingleton.instance?.addToRequestQueue(stringRequest)
    }

这是我的PHP代码：

<?php

define('HOST', 'localhost');
define('USER', '***');
define('PASS', '***');
define('DB', '***');

$con = mysqli_connect(HOST,USER,PASS,DB);

$name = $_POST['name'];
$password = $_POST['password'];

$sql = "select * from *** where name = '$name' and password = '$password';";

$res = mysqli_query($con,$sql);
$check = mysqli_fetch_array($res);

if(isset($check)){
echo 'success';
}
else{
echo 'failure';
}

mysqli_close($con);
?>

实际上我想要的只是如果我输入正确的名称和密码，那么我将进入Php echo 'success';我希望在我的函数checking中有一种会说成功的Toast连接。我尝试但我不知道如何修改我的代码。非常感谢您的建议！

Answer 1

我不知道kotlin但是如果你能在这里做出来的话就是制作祝酒词的java代码。

Toast toast = Toast.makeText(getApplicationContext(), "successful connection", Toast.LENGTH_SHORT).show;

您需要导入android.widget.Toast 有关更多详细信息和培训，请访问官方网站here。

修改好吧，我已经说过我不知道kotlin但也许可以试试这段代码。

private fun checking(){ val name: String = editText?.text.toString() val password: String = editText2?.text.toString() val temp: String ="pass" //Creating a new string I dont know if it is dont this way val stringRequest = object : StringRequest(Request.Method.POST, 192.168.1.50, Response.Listener<String> { response -> try { val obj = JSONObject(response) Toast.makeText(applicationContext, obj.getString("message"), Toast.LENGTH_LONG).show() } catch (e: JSONException) { e.printStackTrace() } }, object : Response.ErrorListener { override fun onErrorResponse(volleyError: VolleyError) { Toast.makeText(applicationContext, volleyError.message, Toast.LENGTH_LONG).show() temp="fail" //Setting the temp string to fail. dont know if it dont this way either } }) { @Throws(AuthFailureError::class) override fun getParams(): Map<String, String> { val params = HashMap<String, String>() params.put("name", name) params.put("password", password) return params } } if(temp.isEqual("pass")) // checkig if temp was changed or not { Toast toast = Toast.makeText(getApplicationContext(), "successful connection", Toast.LENGTH_SHORT).show; } VolleySingleton.instance?.addToRequestQueue(stringRequest) }

请不要指出我的synatx是否错误。我不知道Kotlin的K.

Answer 2

在您的情况下，要在Toast语法中创建Kotlin，语法为：

Toast.makeText(this@MainActivity,obj.getString("message"),Toast.LENGTH_SHORT).show()

将此行替换为现有的Toast Line

创建要登录的活动

2 个答案: