当我使用方向键时,Curses get_key不返回任何输入

时间:2017-06-26 17:20:50

标签: python curses

我使用终端和pythons curses模块制作了游戏。我使用kbinput函数操纵蛇。这适用于数字键盘和标准字母,但是,当我尝试使用方向键时,它会抛出异常_cureses_error: no input如果我按住键,最终其中一个命令将最终通过。我有完全阻塞模式,所以获得无输入异常是没有意义的。

我尝试了一个快速测试,看看它是否在一个线程中运行是一个问题,但在我的测试用例中,方向键工作正常。

相关功能如下:

def game():
    screen=curses.initscr()
    curses.start_color()
    curses.raw()
    curses.cbreak()
    curses.noecho()
    screen.keypad(True)
    try:
        gtime=time.time()
        b=Board(screen)
        s=Snake(b)
        #thread.start_new_thread(steps,(s,b))
        thread.start_new_thread(kbinput,(s,b,screen))
        ....

def kbinput(snake,b,screen):
    while snake.alive==True:
        key=""
        key=screen.getkey()
        b.key=key
        if key=="q":
            snake.alive=False
            break
        elif (key == "8" or key == "i" or key == 'KEY_UP') and snake.direction != 3: snake.direction=1
        elif (key == "6" or key == "l" or key == 'KEY_RIGHT') and snake.direction != 4: snake.direction=2
        elif (key == "4" or key == "j" or key == 'KEY_LEFT') and snake.direction != 2: snake.direction=4
        elif (key == "5" or key == "k" or key == 'KEY_DOWN') and snake.direction != 1: snake.direction=3
    return

编辑: 托马斯是正确的,问题似乎是线程化kbinput。为了解决这个问题,我对这些函数进行了这些更改:

def game():
    screen=curses.initscr()
    curses.start_color()
    curses.raw()
    curses.cbreak()
    curses.noecho()
    screen.keypad(True)
    curses.halfdelay(1)
    curses.init_pair(1,curses.COLOR_RED,curses.COLOR_BLACK)
    curses.init_pair(2,curses.COLOR_GREEN,curses.COLOR_BLACK)
    try:
        gtime=time.time()
        b=Board(screen)
        s=Snake(b)
        #thread.start_new_thread(kbinput,(s,b,screen))
        while s.alive and s.x != 0 and s.x != b.width-1 and s.y !=1 and  s.y != b.height-2:
            kbinput(s,b,screen)
            gtime=time.time()
            update(s,b,screen)
            if snake_check(s) == True: break

def kbinput(snake,b,screen):
    #while snake.alive==True:
        key=""
        key2=screen.getch()
        if key2==-1: return
        try:key=chr(key2)
        except:pass
        if key=="q":
            snake.alive=False
            #break
        elif (key == "8" or key == "i" or key2 == curses.KEY_UP) and snake.direction != 3: snake.direction=1
        elif (key == "6" or key == "l" or key2 == curses.KEY_RIGHT) and snake.direction != 4: snake.direction=2
        elif (key == "4" or key == "j" or key2 == curses.KEY_LEFT) and snake.direction != 2: snake.direction=4
        elif (key == "5" or key == "k" or key2 == curses.KEY_DOWN) and snake.direction != 1: snake.direction=3
        return

1 个答案:

答案 0 :(得分:1)

而不是寻找字符串文字

key == 'KEY_UP')

寻找定义常数

key == curses.KEY_UP)

虽然如评论中所述,但这需要getch方法。

然而,这一行表明一个更严重的问题:

thread.start_new_thread(kbinput,(s,b,screen))

一般来说,Curses不是线程安全的(并且python的curses绑定受此限制):