Question

我将关系保存到一个数据透视表，该数据透视表将helpdesk_ticket连接到user_id，并附加一列描述他们上次查看故障单的时间。我找到了一个解决方案，但我正在寻找一种方法来优化它，因为它似乎有点hacky。

我发回的对象是与所附用户关系的已保存关系。

 $involved = HelpdeskTicketInvolved::where('helpdesk_ticket_id', $ticket_involved_user->helpdesk_ticket_id)->where('users_id', $ticket_involved_user->users_id)->with('user')->first();

正如预期的那样，我得到了以下对象。

{
  "id": 27,
  "helpdesk_ticket_id": 1,
  "users_id": 20,
  "ticket_notifications": 1,
  "ticket_emails": 1,
  "created_at": "2017-06-26 10:13:00",
  "updated_at": "2017-06-26 10:13:00",
  "viewed_at": null
  "user": {
    "id": 20,
    "name": "Nate",
    "username": "nate",
    "email": "nate@email.com",
    "config": "",
    "ad_connected": true,
    "is_store": false,
    "force_reset": false,
    "disabled": false,
    "last_login": "2017-01-19 08:05:00",
    "created_at": "2016-10-04 18:15:00",
    "updated_at": "2017-05-31 12:00:00",
    "phone": null,
    "district_id": null,
    "deleted_at": null,
   }
}

我真的想要颠倒对象的顺序，以便让用户回过头来保存关系，就像我在下面一样。

{
  "id": 20,
  "name": "Nate",
  "username": "nate",
  "email": "nate@email.com",
  "store_id": 89,
  "config": "",
  "ad_connected": true,
  "is_store": false,
  "force_reset": false,
  "disabled": false,
  "last_login": "2017-01-19 08:05:00",
  "created_at": "2016-10-04 18:15:00",
  "updated_at": "2017-05-31 12:00:00",
  "phone": null,
  "district_id": null,
  "deleted_at": null,
  "pivot": {
    "id": 27,
    "helpdesk_ticket_id": 1,
    "users_id": 20,
    "ticket_notifications": 1,
    "ticket_emails": 1,
    "created_at": "2017-06-26 10:13:00",
    "updated_at": "2017-06-26 10:13:00",
    "viewed_at": null
  }
}

以下是我现在正在使用的代码，但是我对它不满意。什么是优化此方法的最佳方式？

$involved = HelpdeskTicketInvolved::where('helpdesk_ticket_id', $ticket_involved_user->helpdesk_ticket_id)->where('users_id', $ticket_involved_user->users_id)->with('user')->first()->toArray();
        $return = $involved['user'];
        $return['pivot'] = $involved;
        unset($return['pivot']['user']);

        return Response::json($return, 200);

Answer 1

如果我理解正确，你可能会得到你所需要的：

User::with("helpdeskTicketInvolved")->find($userid); // Assuming you know the user id you want.

这假设您的用户模型中包含：

public function helpdeskTicketInvolved() {
       return $this->hasMany(HelpdeskTicketInvolved::class)->withPivot(["ticket_notifications","ticket_emails"])->withTimestamps();
}

寻找一种方法来优化我在laravel中反转物体的方式

1 个答案: