Question

我似乎无法弄清楚如何使用Ajax从jquery ui按钮函数提交表单。

这是我的脚本，通过传统的方式提交表单

        $('#contact-form').dialog({
            modal: true,
            autoOpen: false,
            buttons: {
                Cancel: function () {
                    $(this).dialog('close');
                },
                Ok: function () {
                    $('form#contactUs').submit();
                    $(this).dialog('destroy');
                }
            }
        });

        $('#contact-us').click(function () {
            $('#contact-form').dialog('open');
            return false;
        });
    });

这是我的表格

<div id="contact-form" class="hidden" title="Online Request Form">
    <form action="/Main/Contact/contactUs" method="post">            
        <div>
            <label for="Name">Name</label><br />
            <input name="Name" /><br />
            <label for="PhoneNumber">Phone Number</label><br />
            <input name="PhoneNumber" /><br />
            <label for="EmailAddress">Email Address</label><br />
            <input name="EmailAddress" /><br />
            <label for="Question">Question or Comment</label><br />
            <textarea name="Question"></textarea><br />
            <label for="Security">What color is an orange?</label><br />
            <input name="Security" />
            <noscript>
                <input type="submit" name="submit" value="Ok" />
            </noscript>
        </div>
    </form>    
</div>

如何更改此设置以通过Ajax提交链接以便我可以显示成功消息？

Answer 1

这可能就足够了：

$("#contact-form form").submit(function(e) {
    e.preventDefault();
    $.post( $(this).attr('action'), $(this).serialize(), 
                function(resp) {
                    if(resp == "success") {
                        alert('Submission was successful');
                    } else {
                        // something else
                    }
                }
    });              
});

简要说明：

将onsubmit事件处理程序绑定到联系表单。防止“正常”提交。
序列化表单，并将结果发送到表单的操作。
评估回复，并以某种方式显示消息。

进一步阅读：

Answer 2

这是我找到的解决方案

<div id="contact-form" class="hidden" title="Online Request Form">
    @Using (Ajax.BeginForm("Contact", "Main",
                          Nothing,
                          New AjaxOptions With {.UpdateTargetId = "", .HttpMethod = "post"},
                          New With {.id = "contactUs"}))
        @<div>
            <label for="Name">Name</label><br />
            <input name="Name" /><br />
            <label for="Phone">Phone Number</label><br />
            <input name="Phone" /><br />
            <label for="Email">Email Address</label><br />
            <input name="Email" /><br />
            <label for="Question">Question or Comment</label><br />
            <textarea name="Question"></textarea><br />
            <label for="Security">What color is an orange?</label><br />
            <input name="Security" />
            <noscript>
                <input type="submit" name="submit" value="Ok" />
            </noscript>
        </div>
    End Using
</div>
<script>
    $(function () {
        $('#contact-form').dialog({
            modal: true,
            autoOpen: false,
            buttons: {
                Cancel: function () {
                    $(this).dialog('close');
                },
                Ok: function () {
                    $('form#contactUs').trigger('submit');
                    $(this).submit();
                }
            }
        });

        $('#contact-us').click(function () {
            $('#contact-form').dialog('open');
            return false;
        });
    });

</script>

将jquery.submit转换为ajax submit

2 个答案: