Question

我想从表AnswerSets中插入数据

+-------+---------+------+-----+---------+-------+
| Field | Type    | Null | Key | Default | Extra |
+-------+---------+------+-----+---------+-------+
| Id    | int(11) | YES  |     | NULL    |       |
| Q1    | int(11) | YES  |     | NULL    |       |
| Q2    | int(11) | YES  |     | NULL    |       |
| Q3    | int(11) | YES  |     | NULL    |       |
[...]
+-------+---------+------+-----+---------+-------+

到T_ANSWER_SET。

+--------+---------+------+-----+---------+-------+
| Field  | Type    | Null | Key | Default | Extra |
+--------+---------+------+-----+---------+-------+
| U_ID   | int(11) | YES  |     | NULL    |       |
| Q_ID   | int(11) | YES  |     | NULL    |       |
| ANSWER | int(11) | YES  |     | NULL    |       |
+--------+---------+------+-----+---------+-------+

因此我在一个过程的循环中使用以下查询：

INSERT INTO T_ANSWER_SET (U_ID, Q_ID, ANSWER)
SELECT i, j, (SELECT c FROM AnswerSets WHERE Id = i);

i，j是整数，并且在循环中递增。 c是我想要数据的AnswerSets列的名称（如＆＃39; Q10＆＃39;）。但我总是这样：

+------+------+--------+
| U_ID | Q_ID | ANSWER |
+------+------+--------+
|    1 |    1 |      0 |
|    1 |    2 |      0 |
|    1 |    3 |      0 |
[...]
+------+------+--------+

我希望查询针对i = 3，j = 10和c =＆＃39; Q10＆＃39;：

INSERT INTO T_ANSWER_SET (U_ID, Q_ID, ANSWER)
SELECT 3, 10, (SELECT Q10 FROM AnswerSets WHERE Id = 3);

提前感谢您的帮助。

Answer 1

尝试PREPARE Statement：

MariaDB [(none)]> SET @`i` := 3,
    ->     @`j` := 1,
    ->     @`c` := '`Q10`';
Query OK, 0 rows affected (0.00 sec)

MariaDB [(none)]> SET @`stmt` := CONCAT('
    '> INSERT INTO `T_ANSWER_SET` (`U_ID`, `Q_ID`, `ANSWER`)
    '> SELECT ', @`i`, ', ', @`j`, ', (SELECT ', @`c`, '
    '>                                 FROM `AnswerSets`
    '>                                 WHERE `Id` = ', @`i`, ')
    '> ');
Query OK, 0 rows affected (0.00 sec)

MariaDB [(none)]> SELECT @`stmt`;
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| @`stmt`                                                                                                                                                                              |
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| 
INSERT INTO `T_ANSWER_SET` (`U_ID`, `Q_ID`, `ANSWER`)
SELECT 3, 1, (SELECT `Q10`
              FROM `AnswerSets`
              WHERE `Id` = 3)
 |
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
1 row in set (0.00 sec)

MariaDB [(none)]> -- PREPARE `stmt` FROM @`stmt`;
MariaDB [(none)]> -- EXECUTE `stmt`;
MariaDB [(none)]> -- DEALLOCATE PREPARE `stmt`;

变量不会被其值替换

1 个答案: