Question

我有一个词典列表，例如：

list_of_clients = [
    {"Name": "Alex", "Surname": "Dorfman", ...},
    {"Name": "Serge", "Surname": "Ioffe"}, ...
]

我知道同一个客户端的列表中有重复的词典。

有没有办法快速打印出来？

谢谢！

Answer 1

您可以保留set已见过的名字。您必须定义应考虑哪些密钥。在这种情况下：["Name", "Surname"]。如果您愿意，只需添加更多：

list_of_clients = [{"Name": "Alex", "Surname": "Dorfman"}, {"Name": "Serge", "Surname": "Ioffe"}, {"Name": "Alex", "Surname": "Dorfman"}, {"Name": "Serge", "Surname": "Ioffe"}]

already_seen = set()

for client in list_of_clients:
    complete_name = tuple(client.get(k) for k in ["Name", "Surname"])
    if complete_name in already_seen:
        print("Duplicate : %s" % (complete_name,))
    already_seen.add(complete_name)

输出：

Duplicate : ('Alex', 'Dorfman')
Duplicate : ('Serge', 'Ioffe')

Answer 2

您可以尝试：

res = set(tuple(client.items() 
                for client in list_of_clients 
                if list_of_clients.count(client) > 1))

set()将删除结果中的重复项，并且tuple()是必需的（至少在Python3中），因为items（）本身仍然不可清除。

正如其他人所说，这不会使项目保持有序，但如果您只想删除重复项，这就足够了。

如何在列表中快速找到重复的词典？

2 个答案: