Question

我已将DLL导入到我的程序中，并且有以下几个函数：

typedef int (*FEEDQ_CALLBACK)           ( long nSD, long nQtype,  long nNumber ) ;
typedef int (*CALLDISP_CALLBACK)        ( AODFeedDispositionBase* CallDisposition );
typedef int (*SERVICE_STATUS_CALLBACK)  ( long nSD, long nStatus ) ;
typedef int (*AUTH_SERVICE_CALLBACK)    ( long nSD, char* sSDesc, long nSType ) ;
typedef int (*INBOUND_ABANDON_CALLBACK) ( long nSD, DCCProInboundDisposition* inbounCall ) ;
typedef int (*SESSION_STATUS_CALLBACK)  ( long lTypeId, long lStatus ) ;

extern "C"
{
    //Methods
    AODFEEDAPI short Initialize(const char * sTenantName, const char * sUserID, const char * sPassword, AUTH_SERVICE_CALLBACK pAuthSrvFunc, SERVICE_STATUS_CALLBACK pSrvStatFunc, FEEDQ_CALLBACK pFeedQFunc, CALLDISP_CALLBACK pCallDispFunc, INBOUND_ABANDON_CALLBACK pInboundCallFunc, SESSION_STATUS_CALLBACK pSessionStatFunc = 0);
    AODFEEDAPI short Close();   
    AODFEEDAPI short StopService( long nServiceID, long nQueueAction );
    AODFEEDAPI short StartService(long nServiceID);
}

我想调用DLL中的Initialize()函数。我对如何在回调函数中传递参数感到困惑。

Answer 1

您不会将参数传递给回调。回调函数是您在自己的代码中定义的函数，然后提供给DLL，以便它可以在需要时调用它们，并将参数传递给您。例如：

int MyFeedQCallback( long nSD, long nQtype, long nNumber )
{
    // do something... 
} 

int MyCallDispCallback( AODFeedDispositionBase* CallDisposition )
{
    // do something... 
}

int MyServiceStatusCallback( long nSD, long nStatus )
{
    // do something... 
}

int MyAuthServiceCallback( long nSD, char* sSDesc, long nSType )
{
    // do something... 
}

int MyInboundAbandonCallback( long nSD, DCCProInboundDisposition* inbounCall )
{
    // do something... 
}

int MySessionStatusCallback( long lTypeId, long lStatus )
{
    // do something... 
}

int main()
{
    ...
    short ret = Initialize("tenant name", "user ID", "password", &AuthServiceCallback, &MyServiceStatusCallback, &MyFeedQCallback, &MyCallDispCallback, &MyInboundAbandonCallback, &MySessionStatusCallback);
    ...
    long serviceID = ...;
    StartService(serviceID);
    ...
    StopService(serviceID, queueAction);
    ...
    Close();
    return 0;
}

C ++导入DLL并使用其回调函数

1 个答案: