我刚刚开始将Redux集成到我的第一个React Native(Expo.io)项目中。我已经登录了Redux,但是当我尝试在我的应用程序的某个屏幕上创建一个注销按钮时,它实际上会在加载后立即触发注销。我想我必须误解Redux连接和mapDispatchToProps的工作方式。我已多次阅读文档,但仍然卡住了。这是代码处于非工作状态。
登录 - 一直工作,直到我在个人资料页面上添加退出调度
import { connect } from "react-redux";
import React, { Component } from "react";
import {
Button,
View,
Text,
ActivityIndicator,
Alert,
FlatList
} from "react-native";
import { NavigationActions } from "react-navigation";
import { SocialIcon, Card } from "react-native-elements";
import Reactotron from "reactotron-react-native";
import { logIn } from "../actions";
import { signIn } from "../components/Auth";
class SignIn extends Component {
async handleClick() {
res = await signIn();
if (res != false) {
this.props.logIn(res.token);
} else {
console.log("Login Failed");
}
}
render() {
return (
<View style={{ paddingVertical: 20 }}>
<Card title="finis Requires A Facebook Account To Operate">
<SocialIcon
title="Fred"
button
type="facebook"
onPress={() => this.handleClick()}
/>
</Card>
</View>
);
}
}
const mapDispatchToProps = dispatch => {
return {
logIn: fbToken => {
dispatch(logIn(fbToken));
}
};
};
LoginScreen = connect(null, mapDispatchToProps)(SignIn);
export default LoginScreen;
减速
import { combineReducers } from "redux";
import Reactotron from "reactotron-react-native";
import { LOG_IN, LOG_OUT, ADD_PHONE_CONTACTS } from "../actions/actions";
const initialState = {
signedIn: false,
fbToken: "fred",
test: undefined,
phoneContacts: {}
};
const finis = combineReducers({
auth,
phoneContacts
});
function auth(state = initialState, action) {
switch (action.type) {
case LOG_IN:
Reactotron.log("LOG IN");
return {
...state,
signedIn: true,
fbToken: action.fbToken
};
case LOG_OUT:
Reactotron.log("LOG OUT");
return {
...state,
signedIn: false,
fbToken: undefined
};
default:
return state;
}
}
function phoneContacts(state = [], action) {
switch (action.type) {
case ADD_PHONE_CONTACTS:
console.log("Adding Contacts");
return {
...state,
phoneContacts: action.phoneContacts
};
default:
return state;
}
}
export default finis;
个人资料不工作。在没有按下按钮的情况下触发LOG_OUT动作。
import React, { Component } from "react";
import { Button, Card } from "react-native-elements";
import { View, Text, ActivityIndicator, AsyncStorage } from "react-native";
import { MapView } from "expo";
import { connect } from "react-redux";
import { bindActionCreators } from "redux";
import { SimpleLineIcons } from "@expo/vector-icons";
import Reactotron from "reactotron-react-native";
import * as ActionCreators from "../actions";
import { signOut } from "../components/Auth";
class ProfileWrap extends Component {
handleClick() {
Reactotron.log(this.Actions);
this.props.logOut();
}
render() {
return (
<View style={{ paddingVertical: 20 }}>
<Card title="Profile">
<View
style={{
backgroundColor: "#bcbec1",
alignItems: "center",
justifyContent: "center",
width: 80,
height: 80,
borderRadius: 40,
alignSelf: "center",
marginBottom: 20
}}
>
<Text style={{ color: "white", fontSize: 28 }}>JD</Text>
</View>
<Button title="Log Out" onPress={this.handleClick} />
</Card>
</View>
);
}
}
mapDispatchToProps = dispatch => {
return {
logOut: dispatch(logOut())
};
};
const Profile = connect(null, mapDispatchToProps)(ProfileWrap);
export default Profile;
任何帮助都会受到赞赏,即使它告诉我我做错了所有的事情:)已经持续数小时了。
NEW Profile.js - Gives无法读取未定义的属性'logOut'
import React, { Component } from "react";
import { Button, Card } from "react-native-elements";
import { View, Text, ActivityIndicator, AsyncStorage } from "react-native";
import { MapView } from "expo";
import { connect } from "react-redux";
import { SimpleLineIcons } from "@expo/vector-icons";
import { logOut } from "../actions";
import { signOut } from "../components/Auth";
class ProfileWrap extends Component {
handleClick() {
console.log(this.props);
this.props.logOut();
}
render() {
return (
<View style={{ paddingVertical: 20 }}>
<Card title="Profile">
<View
style={{
backgroundColor: "#bcbec1",
alignItems: "center",
justifyContent: "center",
width: 80,
height: 80,
borderRadius: 40,
alignSelf: "center",
marginBottom: 20
}}
>
<Text style={{ color: "white", fontSize: 28 }}>JD</Text>
</View>
<Button title="Log Out" onPress={this.handleClick} />
</Card>
</View>
);
}
}
const mapDispatchToProps = dispatch => {
return {
logOut: function() {
dispatch(logOut());
}
};
};
const Profile = connect(null, mapDispatchToProps)(ProfileWrap);
export default Profile;
答案 0 :(得分:1)
您的mapDispatchToProps
应该返回一个带有功能的对象。你现在拥有它的方式,logOut()
将被立即调用,因为它不在函数内部。将其更改为此应修复它:
const mapDispatchToProps = dispatch => {
return {
logOut: function () {
dispatch(logOut());
}
};
};
这是一种更简洁的方法:
const mapDispatchToProps = dispatch => ({
logOut() {
dispatch(logOut());
}
});
此外,您在const
前面遗失了mapDispatchToProps
,但这不会影响任何内容。
编辑:
您现在不必使用它,但它将来会有所帮助 - 如果您的组件仅使用render
方法,则可以将其更改为无状态功能组件。目前推荐的方法是尽可能创建组件:
const ProfileWrap = props => (
<View style={{ paddingVertical: 20 }}>
<Card title="Profile">
<View
style={{
backgroundColor: "#bcbec1",
alignItems: "center",
justifyContent: "center",
width: 80,
height: 80,
borderRadius: 40,
alignSelf: "center",
marginBottom: 20
}}
>
<Text style={{ color: "white", fontSize: 28 }}>JD</Text>
</View>
<Button title="Log Out" onPress={props.logOut} />
</Card>
</View>
);