一个collectionView中不同类型的单元格

时间:2017-06-25 18:50:27

标签: swift uicollectionview switch-statement uicollectionviewcell indexpath

我在一个控制器中有4个不同的collectionView,在第一个collectionView中我希望显示3个不同的单元格。在下面的代码中,应用程序不会崩溃,但在第一个indexPath.item为0时,仅加载案例0 :(“cellId”)。它不会加载其他2个案例。在此先感谢您的帮助!

    func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {

        if indexPath.item == 0 {
             switch indexPath.item {
            case 0:
                return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId", for: indexPath)
            default:
                return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId4", for: indexPath)
            }

        } else if indexPath.item == 1 {
            return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId2", for: indexPath)

        } else if indexPath.item == 2 {
            return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId3", for: indexPath)

        } else {

        let myCell = collectionView.dequeueReusableCell(withReuseIdentifier: "cellId", for: indexPath)
        return myCell

        }
    }

// 2 collectionView Cells - 每个单元格中只有1个部分
   // cell 1 - collectionViewController中的withReuseIdentifier“cellId”

class TravelGuideHomeCellForStats: BaseHomeCell, UICollectionViewDataSource, UICollectionViewDelegate, UICollectionViewDelegateFlowLayout {

    lazy var collectionView: UICollectionView = {
        let layout = UICollectionViewFlowLayout()
        let cv = UICollectionView(frame: .zero, collectionViewLayout: layout)
        cv.backgroundColor = UIColor.white
        cv.dataSource = self
        cv.delegate = self
        return cv
    }()

    let cellId = "cellId"


    override func setupViews() {
        super.setupViews()

        collectionView.register(BaseTravelGuideHomeCell.self, forCellWithReuseIdentifier: cellId)
    }

    func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {
        return 1
    }

    func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {
        let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "cellId", for: indexPath) as! BaseTravelGuideHomeCell

        return cell
    }

}

// cell 2 - collectionViewController中的withReuseIdentifier“cellId4”

class TravelGuideCommentsCell: BaseCommentsCell, UICollectionViewDataSource, UICollectionViewDelegate, UICollectionViewDelegateFlowLayout {

    lazy var collectionView: UICollectionView = {
        let layout = UICollectionViewFlowLayout()
        let cv = UICollectionView(frame: .zero, collectionViewLayout: layout)
        cv.backgroundColor = UIColor.white
        cv.dataSource = self
        cv.delegate = self
        return cv
    }()

    let cellId = "cellId"

    override func setupViews() {
        super.setupViews()

        collectionView.register(BaseTravelGuideCommentsCell.self, forCellWithReuseIdentifier: cellId)
    }

    func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {
        return 1
    }

    func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {
        let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "cellId", for: indexPath) as! BaseTravelGuideCommentsCell

        return cell

    }

}

1 个答案:

答案 0 :(得分:4)

您的意思是先在section进行过滤,而不是在视图控制器中按item进行过滤吗?

即。像这样:

if indexPath.section == 0 {
    switch indexPath.item {
        ...
    }
} else if indexPath.section == 1 {
    return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId2", for: indexPath)

} else if indexPath.section == 2 {
    return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId3", for: indexPath)

} else {

    let myCell = collectionView.dequeueReusableCell(withReuseIdentifier: "cellId", for: indexPath)
    return myCell
}

虽然我会以嵌套开关的方式完成此操作:

switch indexPath.section { 
case 0:
    switch indexPath.item {
    ...
    } 
case 1:
    return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId2", for: indexPath)
case 2:
    return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId3", for: indexPath)
default:
    return collectionView.dequeueReusableCell(withReuseIdentifier: "cellId", for: indexPath)
}