我的文件是书签，backup-6.session
里面的文件是长字母，我需要复制所有网址（很多）看到这里的例子
......"charset":"UTF-8","ID":3602197775,"docshellID":0,"originalURI":"https://www.youtube.com/watch?v=axxxxxxxxsxsx","docIdentifier":470,"structuredCloneState":"AAAAA.....
结果输出text.txt
https://www.youtube.com/watch?v=axxxxxxxxsxsx
https://www.youtube.com/watch?v=bxxxxxxxxsxsx
https://www.youtube.com/watch?v=cxxxxxxxxsxsx
https://www.youtube.com/watch?v=dxxxxxxxxsxsx
....
....
比A "originalURI":"开始以结束"
命令：AWK，SED ..（我不知道对我来说什么是最好的命令） 谢谢
答案 0 :(得分：1)
使用GNU awk进行多字符RS和RT：
$ awk -v RS='"originalURI":"[^"]+' 'sub(/.*"/,"",RT){print RT}' file
https://www.youtube.com/watch?v=axxxxxxxxsxsx
答案 1 :(得分：0)
你也可以使用grep，例如：
import SpriteKit
import GameplayKit
// MARK: - GameScene
class GameScene: SKScene {
// MARK: - Allows me to work with vectors. Derived from https://www.raywenderlich.com/145318/spritekit-swift-3-tutorial-beginners
func subtract(point: CGPoint, fromPoint: CGPoint) -> CGPoint {
return CGPoint(x: point.x - fromPoint.x, y: point.y - fromPoint.y) //Returns a the first vector minus the second
}
func add(point: CGPoint, toPoint: CGPoint) -> CGPoint {
return CGPoint(x: point.x + toPoint.x, y: point.y + toPoint.y) //Returns a the first vector minus the second
}
func multiply(point: CGPoint, by scalar: CGFloat) -> CGPoint {
return CGPoint(x: point.x * scalar, y: point.y * scalar)
}
func divide(point: CGPoint, by scalar: CGFloat) -> CGPoint {
return CGPoint(x: point.x / scalar, y: point.y / scalar)
}
func magnitude(point: CGPoint) -> CGFloat {
return sqrt(point.x*point.x + point.y*point.y)
}
func normalize(aPoint: CGPoint) -> CGPoint {
return divide(point: aPoint, by: magnitude(point: aPoint))
}
// MARK: - Properties
let minDist: CGFloat = 60
var userPath: [CGPoint] = [] //Holds the coordinates collected when the user drags their finger accross the screen
override func didMove(to view: SKView) {
}
// MARK: - Helper methods
func getDistance (fromPoint: CGPoint, toPoint: CGPoint) -> CGFloat
{
let deltaX = fromPoint.x - toPoint.x
let deltaY = fromPoint.y - toPoint.y
let deltaXSquared = deltaX*deltaX
let deltaYSquared = deltaY*deltaY
return sqrt(deltaXSquared + deltaYSquared) //Return the distance
}
func touchDown(atPoint pos : CGPoint) {
userPath = []
self.removeAllChildren()
//Get the first point the user makes
userPath.append(pos)
}
func touchMoved(toPoint pos : CGPoint) {
//Get every point the user makes as they drag their finger across the screen
userPath.append(pos)
}
func touchUp(atPoint pos : CGPoint) {
//Get the last position the user was left touching when they've completed the motion
userPath.append(pos)
//Print the entire path:
print(userPath)
print(userPath.count)
plotNodesAlongPath()
}
/**
Puts nodes equidistance from each other along the path that the user placed
*/
func plotNodesAlongPath() {
//Start at the first point
var currentPoint = userPath[0]
var circleNodePoints = [currentPoint] //Holds the points that I will then use to generate circle nodes
for i in 1..<userPath.count {
let distance = getDistance(fromPoint: currentPoint, toPoint: userPath[i]) //The distance between the point and the next
if distance >= minDist { //If userPath[i] is at least minDist pixels away
//Then we can make a vector that points from currentPoint to userPath[i]
var newNodePoint = subtract(point: userPath[i], fromPoint: currentPoint)
newNodePoint = normalize(aPoint: newNodePoint) //Normalize the vector so that we have only the direction and a magnitude of 1
newNodePoint = multiply(point: newNodePoint, by: minDist) //Stretch the vector to a length of minDist so that we now have a point for the next node to be drawn on
newNodePoint = add(point: currentPoint, toPoint: newNodePoint) //Now add the vector to the currentPoint so that we get a point in the correct position
currentPoint = newNodePoint //Update the current point. Next we want to draw a point minDist away from the new current point
circleNodePoints.append(newNodePoint) //Add the new node
}
//If distance was less than minDist, then we want to move on to the next point in line
}
generateNodesFromPoints(positions: circleNodePoints)
}
func generateNodesFromPoints(positions: [CGPoint]) {
print("generateNodesFromPoints")
for pos in positions {
let firstCircleNode = SKShapeNode(circleOfRadius: 5.0)
firstCircleNode.fillColor = UIColor.blue
firstCircleNode.strokeColor = UIColor.blue
firstCircleNode.position = pos //Put the node in the correct position
self.addChild(firstCircleNode)
}
}
// MARK: - Touch responders
override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
for t in touches { self.touchDown(atPoint: t.location(in: self)) }
}
override func touchesMoved(_ touches: Set<UITouch>, with event: UIEvent?) {
for t in touches { self.touchMoved(toPoint: t.location(in: self)) }
}
override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
for t in touches { self.touchUp(atPoint: t.location(in: self)) }
}
override func touchesCancelled(_ touches: Set<UITouch>, with event: UIEvent?) {
for t in touches { self.touchUp(atPoint: t.location(in: self)) }
}
override func update(_ currentTime: TimeInterval) {
// Called before each frame is rendered
}
}
即如果grep -oh "https://www\.youtube\.com/watch?v=[A-Za-z0-9]*" backup-6.session > text.txt
部分仅包含来自A-Z，a-z或数字0-9的字母，并且后面没有任何字母。
注意grep的标志：
axxxxxxxxsxsx答案 2 :(得分：0)
awk解决方案如下：
awk -F, '{ for (i=1;i<=NF;i++) { if ( $i ~ "originalURI") { spit($i,add,":");print gensub("\"","","g",add[2])":"gensub("\"","","g",add[3])} } }' filename
我们循环遍历用“，”分隔的每个字段，然后对“originalURI”进行模式匹配然后我们使用“：”拆分该字符串，并使用函数gensub拆分和删除引号。
sed解决方案如下：
sed -rn 's/^.*originalURI":"(.*)","docIdentifier.*$/\1/p' filename
使用扩展正则表达式（-r）运行sed并禁止输出（-n）用括号（/ 1）括起来的正则表达式替换字符串，打印结果。