XPath - 如何获取具有相同名称的多个标记的列表

时间:2017-06-24 15:04:39

标签: java xml xpath

<?xml version="1.0"?>
<shop>
    <shoes>
        <brand>Nike</brand>
        <size>13</size>
        <colour>White</colour>
        <price>34.99</price>
        <additional name="abc">123</additional>
        <additional name="def">456</additional>
        <additional name="ghi">789</additional>
        <additional name="jkl">101</additional>
    </shoes>
    <trousers>
        <brand>Levi</brand>
        <size>36</size>
        <legSize>33</legSize>
        <colour>Stonewash</colour>
        <price>69.99</price>
        <additional name="mno">112</additional>
        <additional name="pqr">131</additional>
        <additional name="stu">415</additional>
        <additional name="vwx">161</additional>
    </trousers>
</shop>

鉴于上述xml文件,我如何检索<additional>标记内所有<shoes>标记的列表?我想得到'name'的所有值以及标签之间的数值。像这样:

abc, 123
def, 456
ghi, 789
jkl, 101

问题是我不知道会有多少额外的标签。可能没有,可能有20个。我需要一些方法来计算它们然后删除信息。

2 个答案:

答案 0 :(得分:0)

使用// shoes / additional,您将获得所有节点的列表,并可以使用Java迭代它。

答案 1 :(得分:0)

这是一个使用JDK中的XPath来执行查询的示例。它假定变量xml包含您的XML文档。

XPathFactory factory = XPathFactory.newInstance();
XPath xPath = factory.newXPath();
NodeList nodeList = (NodeList) xPath.evaluate("//shoes/additional", new InputSource(new StringReader(xml)), XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); ++i) {
    String name = nodeList.item(i).getAttributes().getNamedItem("name").getNodeValue();
    String text = nodeList.item(i).getTextContent();
    System.out.println(name + ", " + text);
}