Question

我有一个代码，用于计算使用不同表格的用户的分数我在Codeigniter和sql中通过php写了这个，但是这个问题太慢了

 public function getTopUsers($request) {
        // return $request;

        $query = $this->db->query("
            SELECT * FROM users
            WHERE user_is_block = 0
            AND user_is_paid = 1
            ORDER BY id ASC"
        )->result_array();

        foreach($query as $key=>$value) {
            unset($query[$key]['user_token']);
            unset($query[$key]['user_confirmation_token']);
            unset($query[$key]['user_password']);
            $query[$key]['user_score'] = ( ($this->countInvitationByUserID($query[$key]['id']) * 1000) + ($this->getUserLikedCount($query[$key]['id'])) );
        }

        usort($query, function($a, $b) {
            if($b['user_score'] == $a['user_score'])
                return $a['id'] - $b['id'];
            else
                return $b['user_score'] - $a['user_score'];
        });


        return $query;
    }


    public function countcouponByUserID($id) {
        $query = $this->db->query("
            SELECT * FROM payment, coupon, users
            WHERE payment.payment_coupon_id = coupon.id
            AND coupon.coupon_token = users.user_coupon_token
            AND users.id = ?
            AND payment.payment_status = 1", array($id)
        );
        return $query->num_rows();
    }

    public function getUsertabCount($id) {
        $query = $this->db->query("
            SELECT * FROM `users`, post, `tab`
            WHERE users.id = post.post_user_id
            AND tab.tab_post_id = post.post_id
            AND users.id = ?
            AND post.post_is_active = 1", array($id)
        );
        return $query->num_rows();
    }

现在的问题是这段代码太重而且很慢我如何只用一个查询编写这段代码

感谢

Answer 1

您可以使用JOIN计算单个查询中的所有内容，例如：

SELECT u.id, (COUNT(p.*) * 100  - COUNT(l.*)) AS score
FROM users u LEFT JOIN coupon c ON u.user_coupon_token = c.coupon_token 
LEFT JOIN payment p ON p.payment_coupon_id = c.id
LEFT JOIN post po ON u.id = po.post_user_id
LEFT JOIN like l ON l.like_post_id = po.post_id
WHERE u.user_is_block = 0 
AND u.user_is_paid = 1
AND (p.payment_status IS NULL OR p.payment_status = 1)
AND (po.post_is_active IS NULL OR po.post_is_active = 1)
GROUP BY u.id;

sql - 子查询计算得分

1 个答案: