Question

我正在尝试将两个数组与它们的键和值组合在一起，我有以下PHP代码：

foreach ($_POST['id'] as $key => $value) {
    $id_array[] = $value;
    //$array1[] = $update_array;
}

$id_array = array_fill_keys($id_array, 'id');
// var_dump($array1);
// exit();

foreach ($_POST['hruleid'] as $rkey => $rvalue) {
    $rule_array[] = $rvalue;
}

$rule_array = array_fill_keys($rule_array, 'ruleid');
// $result = array();
// foreach ($id_array as $i => $val) {
//     $result[] = array($val, $rule_array[$i]);
// }

echo "<pre>";
print_r($id_array);
echo "<pre>";
print_r($rule_array);
exit();

及其出局是：

Array
(
    [12] => id
    [15] => id
    [13] => id
    [16] => id
)
Array
(
    [0] => ruleid
    [1] => ruleid
    [2] => ruleid
    [3] => ruleid
 )

我想这样：

 Array
 (
 [0] => Array
    (
        [id] => 12
        [ruleid] => 0
    )

[1] => Array
    (
        [id] => 15
        [ruleid] => 1
    )
[2] => Array
    (
        [id] => 13
        [ruleid] => 2
    )
[3] => Array
    (
        [id] => 16
        [ruleid] => 3
    )
 )

我在注释代码中尝试过，但它显示错误。我做错了什么？

Answer 1

使用foreach合并为预期结果

更新1 ：代码的简化版

if(count($_POST['id'])==count($_POST['hruleid']))
 {

     foreach ($_POST['id'] as $key => $value)
     {

        $new_array[] = array('id'=>$value,'rule_id'=>$_POST['hruleid'][$key]);

     }


 }

旧更新：

<?php

$id_array = Array(12,15,13,16);
$rule_array = Array (0,1,2,3);

foreach($id_array as $key=>$row)
{
    $new_array[]= array('id'=>$row,'rule_id'=>$rule_array[$key]);
}

print_r($new_array);


?>

注意：上述代码仅在两个数组具有相同的键和相同的数组计数时才有效

Answer 2

嘿，请检查这个解决方案。这是正确的解决方案，有两个数组，一个是数据，另一个是最终数据。最终数据存储数据数组的值。此逻辑用于Web服务。

  <?php 


        $data = array();
        $final_data = array();

        extract($_POST);

        for ($i=0; $i <sizeof($id) ; $i++) { 

            $data['id'] = $id[$i]; 
            $data['ruleid'] = $hruleid[$i];
            $final_data[] = $data;
        }


        echo '<pre>';
        print_r($final_data);
        echo '</pre>';
 ?>

Answer 3

试试这个

 foreach ($_POST['id'] as $key => $value) {
        $id_array[] = $value;
    }
    foreach ($_POST['hruleid'] as $rkey => $rvalue) {
        $rule_array[] = $rvalue;
    }
    $final=[];
    foreach ($id_array as $key=>$id){
        $final[]=['id'=>$id,'ruleid'=>(isset($rule_array[$key]))?$rule_array[$key]:''];
    }

如果你的数组是

 $id_array=[11,21,13,14];
 $rule_array=[2,3,5,6];

上面的代码将返回值

Answer 4

使用此脚本更改您的php脚本，不需要#include <iostream> using namespace std; int main() { int n, k = 0, x, middle, ok, i, up; cout << "n="; cin >> n; x = n; while (x) { k++; x /= 10; } if (k % 2 == 0) middle = k / 2; else middle = k / 2 + 1; ok = 1; up = n % 10; for (i = 0; i <= up && ok != 1; i++) { n = n / 10; if (up > n % 10) ok = 0; } if (ok == 1) { up = n % 10; for (i = k - up; i < 0 && ok == 1; i--) { n = n / 10; if (up < n % 10) ok = 0; } if (ok == 1) cout << "Evrika! Your number has a mountain appearance"; else cout << "No mountain appearance"; } else cout << "No mountain appearance"; }

array_fill()

这里有一个工作小提琴php fiddle

Answer 5

<强>脚本

akshay@db-3325:/tmp$ cat test.php
<?php

$arr1=array(
    12 => 'id',
    15 => 'id',
    13 => 'id',
    16 => 'id',
);
$arr2 =array(
    0 => 'ruleid',
    1 => 'ruleid',
    2 => 'ruleid',
    3 => 'ruleid',
 );

print_r( 
   array_map(
      function($a,$b){ return array('id'=>$a,'ruleid'=>$b); },
      array_keys($arr1), 
      array_keys($arr2)
   ) 
 );

?>

<强>输出

akshay@db-3325:/tmp$ php test.php 
Array
(
    [0] => Array
        (
            [id] => 12
            [ruleid] => 0
        )

    [1] => Array
        (
            [id] => 15
            [ruleid] => 1
        )

    [2] => Array
        (
            [id] => 13
            [ruleid] => 2
        )

    [3] => Array
        (
            [id] => 16
            [ruleid] => 3
        )

)

将两个数组中的键和值组合成组

5 个答案: