Question

我需要帮助编写动态表的值到SQL的插入，这是我的PHP代码

 <?php 
     require_once('../../../mysqlConnector/mysql_connect.php');

    $query= "INSERT INTO spotreportref (spotreportID,numfire,typefire,numdrug,typedrug) VALUES (); "; 
     $resultID=mysqli_query($dbc,$query);

     echo $id;
    echo $txtnumfire;
     echo $txttypefire;
    echo $txtnumdrug;
    echo $txttypedrug;

    }?>

这是我的添加脚本，我只需要将值保存到我不知道该怎么做的数据库中。

<script type=text/javascript>



var addButton=document.getElementById("add-button"); 

//listen to add button. If clicked, store the entered data and append them in the display
addButton.addEventListener('click', add_row, false);

function add_row(){
 event.preventDefault();
 var new_numfire=document.getElementById("txtnumfire").value;
 var new_typefire=document.getElementById("txttypefire").value;
 var new_numdrug=document.getElementById("txtnumdrug").value;
 var new_typedrug=document.getElementById("txttypedrug").value;

 var table=document.getElementById("data_table");
 var table_len=(table.rows.length)-1;

 var row = table.insertRow(table_len).outerHTML=
 "<tr id= 'row"+table_len+"'>\
    <td id='numfire_row"+table_len+"'>"+new_numfire+"</td>\
    <td id='typefire_row"+table_len+"'>"+new_typefire+"</td>\
     <td id='numdrug_row"+table_len+"'>"+new_numdrug+"</td>\
    <td id='typedrug_row"+table_len+"'>"+new_typedrug+"</td>\
    <td><input type='button' id='edit_button"+table_len+"</td>\
        <input type='button' id='save_button"+table_len+"' value='Save' class='save' onclick='save_row("+table_len+")'> \
        <input type='button' value='Delete' class='delete' onclick='delete_row("+table_len+")'>\
    </td>\
 </tr>";


}

 </script>

Answer 1

出于安全原因，您应该使用预准备语句，所以......

$query= "INSERT INTO spotreportref (spotreportID,numfire,typefire,numdrug,typedrug) VALUES (?,?,?,?,?); "; 
$result=$dbc->mysqli_prepare($query);
$result->bind_param("issss", $id, $txtnumfire, $txttypefire, $txtnumdrug,  $txttypedrug);
$result->execute();

问题是如何获取$ id等的值。如果你发布它们，它将是$_POST[]

如何使用Javascript和PHP将动态表值插入SQL

1 个答案: