Question

我需要一个帮助。我在使用Python和Django迁移模型文件时遇到以下错误。我在解释下面的错误。

     Traceback (most recent call last):
  File "manage.py", line 22, in <module>
    execute_from_command_line(sys.argv)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/__init__.py", line 363, in execute_from_command_line
    utility.execute()
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/__init__.py", line 355, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 283, in run_from_argv
    self.execute(*args, **cmd_options)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 327, in execute
    self.check()
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 359, in check
    include_deployment_checks=include_deployment_checks,
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/commands/migrate.py", line 62, in _run_checks
    issues.extend(super(Command, self)._run_checks(**kwargs))
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 346, in _run_checks
    return checks.run_checks(**kwargs)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/registry.py", line 81, in run_checks
    new_errors = check(app_configs=app_configs)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/urls.py", line 16, in check_url_config
    return check_resolver(resolver)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/urls.py", line 26, in check_resolver
    return check_method()
  File "/usr/local/lib/python2.7/dist-packages/django/urls/resolvers.py", line 254, in check
    for pattern in self.url_patterns:
  File "/usr/local/lib/python2.7/dist-packages/django/utils/functional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "/usr/local/lib/python2.7/dist-packages/django/urls/resolvers.py", line 405, in url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
  File "/usr/local/lib/python2.7/dist-packages/django/utils/functional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "/usr/local/lib/python2.7/dist-packages/django/urls/resolvers.py", line 398, in urlconf_module
    return import_module(self.urlconf_name)
  File "/usr/lib/python2.7/importlib/__init__.py", line 37, in import_module
    __import__(name)
  File "/opt/lampp/htdocs/carClinic/carClinic/urls.py", line 7, in <module>
    url(r'^admin/', admin.site.urls),
  File "/usr/local/lib/python2.7/dist-packages/django/contrib/admin/sites.py", line 280, in urls
    return self.get_urls(), 'admin', self.name
  File "/usr/local/lib/python2.7/dist-packages/django/contrib/admin/sites.py", line 264, in get_urls
    url(r'^%s/%s/' % (model._meta.app_label, model._meta.model_name), include(model_admin.urls)),
AttributeError: 'Personal' object has no attribute 'urls'

我正在解释下面的代码。

models.py：

from __future__ import unicode_literals

from django.db import models
from django.contrib import admin
from datetime import datetime

class Service(models.Model):
    """In this class the columns for service table has declared"""
    cname = models.CharField(max_length=200)
    date_of_service = models.DateTimeField(default=datetime.now, blank=True)
    vechile_no = models.CharField(max_length=200)
    service_type = models.CharField(max_length=200)

class Personal(models.Model):
    """In this class the columns for Person table has declared"""
    name = models.CharField(max_length=200)
    address = models.CharField(max_length=200)
    phone = models.CharField(max_length=15)
    driving_license = models.CharField(max_length=200)
    email = models.CharField(max_length=200)
    date = models.DateTimeField(default=datetime.now, blank=True)

admin.site.register(Service, Personal)

urls.py：

from django.conf.urls import url, include
from django.contrib import admin
admin.autodiscover()

urlpatterns = [
    url(r'^admin/', admin.site.urls),
]

这里我需要在管理面板中显示这两个类。请帮我解决这个问题。

Answer 1

这是问题所在：

admin.site.register(Service, Personal)

上述调用的第二个参数应该是ModelAdmin子类，而是传递Personal模型。其中自然没有urls属性。

Reference：

AdminSite.register（model_or_iterable，admin_class = None，   **选项）
  使用给定的admin_class注册给定的模型类（或可迭代的类）。 admin_class默认为ModelAdmin

这样的代码应该按照惯例而不是models.py放在admin.py中，它应该看起来像

admin.site.register(Personal)
admin.site.register(Service)

如果您想使用自己的自定义ModelAdmin

class ServiceAdmin(admin.ModelAdmin):
    list_fields = ['cname','date_of_service']

admin.site.register(Service, ServiceAdmin)

使用Django和python迁移模型时出错

1 个答案: