Question

我想创建一个视图来显示来自这3个表的计数数据，其中有条件＆＃34;，有些＆＃34;没有where条件＆＃34;。

我第一次计算两次COUNT（e.user_id）的地方没有任何WHERE子句第二次计算＆＃34; WHERE e.reg_date = CURDATE（）＆＃34;

对于第1部分，它不起作用，当我想获得没有任何where子句的user_id的总数时，它默认采取＆＃34; WHERE e.reg_date = CURDATE（）＆＃34;对于这两种情况。

以下是代码：

CREATE OR REPLACE VIEW admin_summary AS (
SELECT COUNT(e.user_id) AS total_register_user, COUNT(e.user_id) AS register_today, COUNT(d.pr_status) AS total_pending_payment , COUNT(f.status) AS total_pending_account, COUNT(g.time) AS failed_login_today
FROM client e, payment d, masterbroker f, login_attempts g
WHERE e.reg_date = CURDATE() AND d.pr_status = 'pending' AND f.status ='pending' AND g.time = CURDATE()
  );

更新1：数据记录：注册用户总数2（所有时间）立即注册：0 待付款总额：1 总待定帐户：1 登录失败：1

这是scaisEdge代码的显示方式。

更新2： 数据样本客户表

masterbroker

付款

更新3：

由于数据类型混乱，我将登录尝试时间更改为datetime。

登录尝试

更新4：使用调试结果似乎没有条件它在某些时候起作用。但我需要Where Where条件。这是没有where子句的结果：

     SELECT COUNT(e.user_id) AS total_register_user , SUM( CASE WHEN 
    date(e.reg_date) = CURDATE() THEN 1 ELSE 0 END) AS register_today , 
    COUNT(d.pr_status) AS total_pending_payment , 
    COUNT(f.status) AS total_pending_account , 
    COUNT(g.time) AS failed_login_today 
   from client e INNER JOIN payment d on e.user_id = d.user_id 
   INNER JOIN masterbroker f on e.user_id = f.user_id 
   INNER JOIN login_attempts g on e.user_id = g.user_id

但总注册用户显示1实际应该是2。

更新5：有关唯一索引的更多信息（如果需要）。 User_id是客户端表的PK＆amp; forgien key for other 3 table，payment，login_attempts＆amp; masterbroker。我有以下独特的索引：

masterbrokerindex ON masterbroker(user_id,accountno, broker_id);
paymentindex ON payment(user_id,pr_rqtime);
login_attempts_index ON login_attempts (user_id,ip);

Answer 1

只关注问题的相关部分，获得两个不同数量的相同数据在不同的条件下你应该使用自联接以两种不同的方式使用tabl

 SELECT 
    COUNT(e1.user_id) AS total_register_user
  , COUNT(e2.user_id) AS register_today
from client e1 
left join client e2 on e1.user_id = e2.user_id and e2.reg_date = CURDATE();
....

或避免连接，您可以使用CASE WHEN过滤e.reg_date

SELECT 
    COUNT(e.user_id) AS total_register_user
  , SUM( CASE WHEN   e.reg_date = CURDATE() THEN 1 ELSE 0 END)  AS register_today
  from client e 
  .....

在您的查询中，表之间没有关系条件。这很不寻常......

并根据您的日期列数据类型（假设e.reg_date是日期时间而g.time是unix时间戳）

  CREATE OR REPLACE VIEW admin_summary AS (
  SELECT 
      COUNT(e.user_id) AS total_register_user
    , SUM( CASE WHEN   date(e.reg_date) = CURDATE() THEN 1 ELSE 0 END)  AS register_today
    , COUNT(d.pr_status) AS total_pending_payment 
    , COUNT(f.status) AS total_pending_account
    , COUNT(g.time) AS failed_login_today
    from client e, payment d, masterbroker f, login_attempts g
  WHERE date(e.reg_date) = CURDATE() 
  AND d.pr_status = 'pending' 
  AND f.status ='pending' 
  AND date(g.time) = CURDATE()
  );

表之间的连接尝试使用

使用左连接中的位置作为内部连接，因此where条件应该对相关的粘土中的条款具有相应性

CREATE OR REPLACE VIEW admin_summary AS (
SELECT 
    COUNT(e.user_id) AS total_register_user
  , SUM( CASE WHEN   date(e.reg_date) = CURDATE() THEN 1 ELSE 0 END)  AS register_today
  , COUNT(d.pr_status) AS total_pending_payment 
  , COUNT(f.status) AS total_pending_account
  , COUNT(g.time) AS failed_login_today
  from client e
  LEFT JOIN payment d on e.user_id = d.user_id 
            AND  date(e.reg_date) = CURDATE() 
            AND d.pr_status = 'pending' 
  LEFT JOIN masterbroker f on e.user_id = f.user_id
            AND f.status ='pending' 
  LEFT JOIN login_attempts g on e.user_id = g.user_id
            AND date(g.time) = CURDATE()
);

如果您不需要在客户端加入付款，可以尝试

  CREATE OR REPLACE VIEW admin_summary AS (
  SELECT 
      COUNT(e.user_id) AS total_register_user
    , SUM( CASE WHEN   date(e.reg_date) = CURDATE() THEN 1 ELSE 0 END)  AS register_today
    , COUNT(d.pr_status) AS total_pending_payment 
    , COUNT(f.status) AS total_pending_account
    , COUNT(g.time) AS failed_login_today
    from client e
    LEFT JOIN  payment d ON  d.pr_status = 'pending' 
    LEFT JOIN masterbroker f on e.user_id = f.user_id
              AND f.status ='pending' 
    LEFT JOIN login_attempts g on e.user_id = g.user_id

    WHERE date(e.reg_date) = CURDATE()          
  );

最后..尝试在没有任何连接的情况下计算pending_payment

  CREATE OR REPLACE VIEW admin_summary AS (
  SELECT 
      COUNT(e.user_id) AS total_register_user
    , SUM( CASE WHEN   date(e.reg_date) = CURDATE() THEN 1 ELSE 0 END)  AS register_today
    , (select COUNT(pr_status) from payment where pr_status = 'pending' ) AS total_pending_payment 
    , COUNT(f.status) AS total_pending_account
    , COUNT(g.time) AS failed_login_today
    from client e
     LEFT JOIN masterbroker f on e.user_id = f.user_id
              AND f.status ='pending' 
    LEFT JOIN login_attempts g on e.user_id = g.user_id
              AND date(g.time) = CURDATE()
  );

Mysql创建视图两个不同的计数在不同条件下具有多个表的相同数据

1 个答案: