Question

我想捕获一个NameError，然后访问该名称并使用它来提供更好的消息。如何在不解析错误消息的情况下访问导致错误的名称？

try:
    love_bug = herbie
except NameError as err:
    name = get_name(err)
    print(name, 'unknown.')

换句话说，如何在上面的代码中实现get_name（）？

Answer 1

您必须从NameError.args[0]：

中抽出名称

>>> try:
...     print(foo)
... except NameError as e:
...     print(re.search("'(?P<name>.+?)'", e.args[0]).group('name'))
...
foo

Answer 2

def get_name(err):
    last = err.find("' ")
    return err[6:last]
try:
    love_bug= heribie
except NameError  as err:
    print(get_name(err.args[0]), "unknown")

Answer 3

如果我理解你的问题，你可以创建自己的错误，如下：

class ValidateName(NameError):
    def __init__(self, name):
        # Call the base class constructor with the parameters it needs
        super().__init__(self, "unknown name " + name) #or whatever you need to add

try:
  love_bug = "herbie"
  raise ValidateName(love_bug) #there is no point in raising the exception manually here, I did this only to show how the message is shown,obliviously somewhere in your code the exception is raised 
except ValidateName as err:
  print(err)

（ValidateName（...），'unknown name herbie'）

如何在NameError中访问名称？

3 个答案: