我有一个名为renderer: function(value, metaData, record, rowIndex, colIndex, store, view) {
if(!value) return '';
var combo = this.columns[colIndex].getEditor();
var combostore = combo.getStore();
var dataIndex = combostore.findExact('id', value);
var recordCombo = combostore.getAt(dataIndex);
return recordCombo.get('name');
},
的表，它具有以下结构：
除了有效日期外，它有许多相同的行。例如：
PF_temo我希望运行一个脚本，删除除最后一列（steve,s,smith, 19710909,112 crazy st,miami,fl,3055551212,201609
steve,s,smith, 19710909,112 crazy st,miami,fl,3055551212,201002
steve,s,smith, 19710909,112 crazy st,miami,fl,3055551212,201706
steve,s,smith, 19710909,112 crazy st,miami,fl,3055551212,199812
）之外的所有内容上匹配的所有重复项，只留下表中的下方，这是{{1}的最新有效日期}：
validitydate这就是我所拥有的;虽然它引发了一个例外：
201706它不起作用，实际上会弹出这个错误：
steve,s,smith, 19710909,112 crazy st,miami,fl,3055551212,201706
另外，我想根据字母表的最后一个字母分阶段运行它。因此需要在某处添加类似DELETE
FROM PF_temp
LEFT OUTER JOIN
(
SELECT Min(ValidityDate) as RowId
, firstname
, middlename
, lastname
, DOB
, address
, city
, state
, phone
FROM PF_temp
GROUP BY firstname
, middlename
, lastname
, DOB
, address
, city
, state
, phone
, validitydate
) as KeepRows
ON TableName.RowId = KeepRows.RowId
WHERE KeepRows.RowId IS NULL
的内容。
答案 0 :(得分：1)
试试这个：
delete a
from PF_Temp a
inner join PF_Temp b
on b.firstname = a.firstname
and b.middlename = a.middlename
and b.lastname = a.lastname
and b.DOB = a.DOB
and b.address = a.address
and b.city = a.city
and b.state = a.state
and b.phone = a.phone
and b.validitydate > a.validitydate
SQL Fiddle处的示例。
以上作品：
a中捕获所有具有重复项的记录。在此阶段，我们会捕获所有记录，因为a中的记录会在b中与自身匹配。validitydate中的b必须大于a中的a，我们都避免上述记录相同的问题（因为如果它是相同的记录，有效日期是相同的），并且如果b中的记录是最新的，也确保不匹配;因为a中没有匹配（即没有更高有效日期的记录）。where a.LastName like 'A%'返回的每条记录;即每个记录都有重复，但有效日期较晚。如果您只想删除具有特定姓氏的重复项，您可以按照上述说法执行操作;即添加行null。
<强>更新
您提到某些列可能包含null != null个。以下是上述修订版，以考虑delete a
from PF_Temp a
inner join PF_Temp b
on ((b.firstname = a.firstname) or (b.firstname is null and a.firstname is null))
and ((b.middlename = a.middlename) or (b.middlename is null and a.middlename is null))
and ((b.lastname = a.lastname) or (b.lastname is null and a.lastname is null))
and ((b.DOB = a.DOB) or (b.DOB is null and a.DOB is null))
and ((b.address = a.address) or (b.address is null and a.address is null))
and ((b.city = a.city) or (b.city is null and a.city is null))
and ((b.state = a.state) or (b.state is null and a.state is null))
and ((b.phone = a.phone) or (b.phone is null and a.phone is null))
and b.validitydate > a.validitydate
。
on coalesce(b.firstname,'') = coalesce(a.firstname)上述的替代方法是delete TheDeletables
from
(
select *
, row_number() over (
partition by
firstname
, middlename
, lastname
, DOB
, address
, city
, state
, phone
order by validitydate desc
) rowid
from PF_Temp
) TheDeletables
where rowid > 1;
（对所有其他匹配字段重复该模式）;虽然这意味着nulls和blanks被视为相同，并且表现不会很好。
替代方法
另一种更宽容空值的方法是使用子查询来回退所有值，使用匹配值对每个集合进行编号，从最近的有效日期开始为1。然后我们删除所有返回的数字大于1的行;即任何具有早期有效日期的重复文件。
{{1}}
演示SQL Fiddle。