我有两个程序:
#line 1 "DB::eval"
234asd
perl < tmp.pl
Bareword found where operator expected at DB::eval line 1, near "234asd"
(Missing operator before asd?)
syntax error at DB::eval line 2, near "234asd
"
Execution of - aborted due to compilation errors.
和第二:
$str = <<CODE;
#line 1 "DB::eval"
234asd
CODE
eval $str;
print $@;
perl < tmp.pl
Bareword found where operator expected at DB::eval line 1, near "#line 1 "DB::eval"
234asd"
(Missing operator before asd?)
syntax error at DB::eval line 2, near "#line 1 "DB::eval"
234asd
"
为什么在第二种情况下我在错误消息中收到了额外的文字:#line 1 "DB::eval"
?我不指望它。
同样在第二种情况下,我不期望额外的新线。我期待:
234asd
"
而不是:
234asd
"
答案 0 :(得分:1)
我不会称这是一个错误,只是依赖于实现的行为。
第二个heredoc变体只包含更多上下文。 没有人保证heredoc的evals与直接脚本的行为相同。
p5p与我达成一致,Zefram没有把它称为bug,SawyerX拒绝了它。