包含对象

Question

我想根据输入的关键字过滤我的数据。

https://jsfiddle.net/LeoCoco/e96L8akn/

let keyword = '-pre';

let data = {
  'Basic': [{
    name: 'a-basic'
  }, {
    name: 'b-basic'
  }, {
    name: 'c-basic'
  }],
  'Premium': [{
    name: 'a-pre'
  }, {
    name: 'b-pre'
  }, {
    name: 'c-pre'
  }],
  'Extra': [{
    name: 'a-ext'
  }, {
    name: 'b-ext'
  }, {
    name: 'c-ext'
  }],
};

输出

'Premium': [{name: 'a-pre'}, { name: 'b-pre'}, { name: 'c-pre'}]

我的尝试

lodash.forEach(data, (card) => {
  card = card.filter(o => {
    return Object.keys(o).some(k => {
      return typeof o[k] === 'string' && o[k].toLowerCase().includes(keyword.toLowerCase());
    });
  });
})

但它不起作用。对我来说，难点在于过滤必须发生在每个数组中包含的嵌套对象键上。

Answer 1

因为这是对象，您可以在reduce()上使用Object.keys()，然后在内部使用every()来检查关键字。

let keyword = '-pre';

let data = {"Basic":[{"name":"a-basic"},{"name":"b-basic"},{"name":"c-basic"}],"Premium":[{"name":"a-pre"},{"name":"b-pre"},{"name":"c-pre"}],"Extra":[{"name":"a-ext"},{"name":"b-ext"},{"name":"c-ext"}]}

var result = Object.keys(data).reduce(function(r, e) {
  var check = data[e].every(o => o.name.indexOf(keyword) != -1);
  if(check) r[e] = data[e]
  return r;
}, {})

console.log(result)

Answer 2

 var result={};
 Object.keys(data).forEach(key => {
   result[key] = data[key].filter(o => {
       return Object.keys(o).some(k =>typeof o[k] === 'string' && o[k].toLowerCase().includes(keyword.toLowerCase()));
  });
})