经过一番搜索,我仍然无法找到解决方案。我是Keras的新手,如果有解决方案我会道歉并且我实际上不明白它与我的问题有什么关系。
我正在使用Keras 2 / Functional API制作一个小型RNN,我无法使Concatenate Layer工作。
这是我的结构:
inputSentence = Input(shape=(30, 91))
sentenceMatrix = LSTM(91, return_sequences=True, input_shape=(30, 91))(inputSentence)
inputDeletion = Input(shape=(30, 1))
deletionMatrix = (LSTM(30, return_sequences=True, input_shape=(30, 1)))(inputDeletion)
fusion = Concatenate([sentenceMatrix, deletionMatrix])
fusion = Dense(122, activation='relu')(fusion)
fusion = Dense(102, activation='relu')(fusion)
fusion = Dense(91, activation='sigmoid')(fusion)
F = Model(inputs=[inputSentence, inputDeletion], outputs=fusion)
这是错误:
ValueError: Unexpectedly found an instance of type `<class 'keras.layers.merge.Concatenate'>`. Expected a symbolic tensor instance.
完整历史记录,如果它有所帮助:
Using TensorFlow backend.
str(inputs) + '. All inputs to the layer '
ValueError: Layer dense_1 was called with an input that isn't a symbolic tensor. Received type: <class 'keras.layers.merge.Concatenate'>. Full input: [<keras.layers.merge.Concatenate object at 0x00000000340DC4E0>]. All inputs to the layer should be tensors.
self.assert_input_compatibility(inputs)
File "C:\ProgramData\Anaconda3\lib\site-packages\keras\engine\topology.py", line 425, in assert_input_compatibility
fusion = Dense(122, activation='relu')(fusion)
File "C:\ProgramData\Anaconda3\lib\site-packages\keras\engine\topology.py", line 552, in __call__
Traceback (most recent call last):
File "C:\ProgramData\Anaconda3\lib\site-packages\keras\engine\topology.py", line 419, in assert_input_compatibility
K.is_keras_tensor(x)
File "C:\ProgramData\Anaconda3\lib\site-packages\keras\backend\tensorflow_backend.py", line 392, in is_keras_tensor
raise ValueError('Unexpectedly found an instance of type `' + str(type(x)) + '`. '
ValueError: Unexpectedly found an instance of type `<class 'keras.layers.merge.Concatenate'>`. Expected a symbolic tensor instance.
我在Windows 7上使用Python 3.6和Spyder 3.1.4。我今天早上用pip升级了TensorFlow和Keras。
感谢您提供的任何帮助!
答案 0 :(得分:25)
尝试:
fusion = concatenate([sentenceMatrix, deletionMatrix])
Concatenate
用于Sequential
模型,而concatenate
用于Functional API
。
答案 1 :(得分:1)
尝试
fusion = Concatenate()([sentenceMatrix, deletionMatrix])