我试图从疫苗详细信息表中删除记录,我试图在phpmyadmin中运行delete语句并且运行完美。但是当我在我的代码中尝试删除语句时,它不会删除记录。任何想法??
<?php
include('connect-db.php');
if (isset($_GET['id']) && is_numeric($_GET['id']))
{
$id = $_GET['id'];
$result = mysql_query("DELETE FROM vaccinedetail WHERE id=$id") or die(mysql_error());
header("Location: start.php");
}
else
{
header("Location: displaytype.php");
}
?>
<table border='1' cellpadding='10'>
<tr>
<th>ID</th>
<th>Vaccine ID</th>
<th>疫苗名稱 (繁體)</th>
<th>疫苗名称 (简体)</th>
<th>Vaccine Name (Eng)</th>
<th>Total no of injection</th>
<th>Nth Injection</th>
<th>Next Injection Skip</th>
<th></th>
</tr>
<?php
include('connect-db.php');
$result = mysql_query("SELECT vaccinedetail.id,vaccinedetail.vaccineid,vaccinedetail.vaccinename1,vaccinedetail.vaccinename2,vaccinedetail.vaccinename3, vaccinedetail.totalnoofinjection,vaccinedetail.nthinjection,vaccinedetail.skip FROM vaccinedetail WHERE vaccinedetail.vaccineid = '" . $_POST['vaccineid'] . "'") or die(mysql_error());
// ^^^ show the specifc type of vaccine taht match the vaccine type in the typeserach.php
?>
<?php
while($row = mysql_fetch_array( $result )) {
?>
<tr>
<td><input type="text" name = "id[]" value="<?php echo $row['id'] ?>"</td>
<td><input type="text" name = "vaccineid[]" value="<?php echo $row['vaccineid'] ?>"</td>
<td><input type="text" name = "vaccinename1[]" value="<?php echo $row['vaccinename1'] ?>"</td>
<td><input type="text" name = "vaccinename2[]" value="<?php echo $row['vaccinename2'] ?>"</td>
<td><input type="text" name = "vaccinename3[]" value="<?php echo $row['vaccinename3'] ?>"</td>
<td><input type="text" name = "totalnoofinjection[]" value="<?php echo $row['totalnoofinjection'] ?>"</td>
<td><input type="text" name = "nthinjection[]" value="<?php echo $row['nthinjection'] ?>"</td>
<td><input type="text" name = "skip[]" value="<?php echo $row['skip'] ?>"</td>
<!--<td><a href="editdisplaytype.php?id=' . $row['id'] . '"><img src="edit.png" width="20px"></a>-->
<td><a href="deletedisplaytype.php?id=' . $row['id'] . '"><img src="delete.jpg" width="20px"></a></td>
</tr>
<?php
}
?>
</table>
答案 0 :(得分:1)
您没有在网址上正确传递id
。
注意:请不要使用 mysql _ ,不推荐使用它们。使用 mysqli _ 或 PDO 。
变化:
<td><a href="deletedisplaytype.php?id=' . $row['id'] . '"><img src="delete.jpg" width="20px"></a></td>
要:
<td><a href="deletedisplaytype.php?id=<?php echo $row['id'];?>"><img src="delete.jpg" width="20px"></a></td>
否则,代码看起来是正确的。
答案 1 :(得分:0)
每个&#39; <td><input>
&#39;你没有关闭输入标签
你的td
<td><input type="text" name = "id[]" value="<?php echo $row['id'] ?>"</td>
关闭后
<td><input type="text" name = "id[]" value="<?php echo $row['id'] ?>"></td>