PHP无法从表中删除记录

时间:2017-06-23 09:37:48

标签: php mysql

我试图从疫苗详细信息表中删除记录,我试图在phpmyadmin中运行delete语句并且运行完美。但是当我在我的代码中尝试删除语句时,它不会删除记录。任何想法??

<?php
include('connect-db.php');

if (isset($_GET['id']) && is_numeric($_GET['id']))
{
    $id = $_GET['id'];
    $result = mysql_query("DELETE FROM vaccinedetail WHERE id=$id") or die(mysql_error());
    header("Location: start.php");
}
else
{
    header("Location: displaytype.php");
}
?>   

<table border='1' cellpadding='10'>
    <tr>
        <th>ID</th>
        <th>Vaccine ID</th>
        <th>疫苗名稱 (繁體)</th>
        <th>疫苗名称 (简体)</th>
        <th>Vaccine Name (Eng)</th>
        <th>Total no of injection</th>
        <th>Nth Injection</th>
        <th>Next Injection Skip</th>
        <th></th>
    </tr>

<?php
include('connect-db.php');

$result = mysql_query("SELECT vaccinedetail.id,vaccinedetail.vaccineid,vaccinedetail.vaccinename1,vaccinedetail.vaccinename2,vaccinedetail.vaccinename3, vaccinedetail.totalnoofinjection,vaccinedetail.nthinjection,vaccinedetail.skip FROM vaccinedetail WHERE vaccinedetail.vaccineid = '" . $_POST['vaccineid'] . "'") or die(mysql_error()); 
// ^^^ show the specifc type of vaccine taht match the vaccine type in the typeserach.php
?>

<?php
while($row = mysql_fetch_array( $result )) {
?>

    <tr>
        <td><input type="text" name = "id[]" value="<?php echo $row['id'] ?>"</td>
        <td><input type="text" name = "vaccineid[]" value="<?php echo $row['vaccineid'] ?>"</td>
        <td><input type="text" name = "vaccinename1[]" value="<?php echo $row['vaccinename1'] ?>"</td>
        <td><input type="text" name = "vaccinename2[]" value="<?php echo $row['vaccinename2'] ?>"</td>
        <td><input type="text" name = "vaccinename3[]" value="<?php echo $row['vaccinename3'] ?>"</td>
        <td><input type="text" name = "totalnoofinjection[]" value="<?php echo $row['totalnoofinjection'] ?>"</td>
        <td><input type="text" name = "nthinjection[]" value="<?php echo $row['nthinjection'] ?>"</td>
        <td><input type="text" name = "skip[]" value="<?php echo $row['skip'] ?>"</td>

        <!--<td><a href="editdisplaytype.php?id=' . $row['id'] . '"><img src="edit.png" width="20px"></a>-->
        <td><a href="deletedisplaytype.php?id=' . $row['id'] . '"><img src="delete.jpg" width="20px"></a></td>
    </tr>
<?php
}
?>
</table>

2 个答案:

答案 0 :(得分:1)

您没有在网址上正确传递id

注意:请不要使用 mysql _ ,不推荐使用它们。使用 mysqli _ PDO

变化:

<td><a href="deletedisplaytype.php?id=' . $row['id'] . '"><img src="delete.jpg" width="20px"></a></td>

要:

<td><a href="deletedisplaytype.php?id=<?php echo $row['id'];?>"><img src="delete.jpg" width="20px"></a></td>

否则,代码看起来是正确的。

答案 1 :(得分:0)

每个&#39; <td><input>&#39;你没有关闭输入标签 你的td

<td><input type="text" name = "id[]" value="<?php echo $row['id'] ?>"</td>

关闭后

<td><input type="text" name = "id[]" value="<?php echo $row['id'] ?>"></td>