Question

我有一个小的python代码，用于列出跨地区的所有EC2实例，但我找不到如何获取Tag＆＃39; Name＆＃39;而我正在打印结果。使用instance.tags打印所有标签，但我只想要＆＃39; Name＆＃39;

代码示例：

import boto3

access_key = "xyw"
secret_key = "xywz"

client = boto3.client('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,region_name='us-east-1')

ec2_regions = [region['RegionName'] for region in client.describe_regions()['Regions']]

for region in ec2_regions:
  conn = boto3.resource('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,
               region_name=region)
  instances = conn.instances.filter()
  for instance in instances:
    if instance.state["Name"] == "running":
      print (region, instance.key_name, instance.public_dns_name, instance.image_id, instance.instance_type, instance.tags)

Answer 1

您需要遍历tags，因此您需要在代码中添加此内容

  for tag in tags:
    if tag["Key"] == 'Name':
        instancename = tag["Value"]

类似这样的事情

import boto3

access_key = "xyw"
secret_key = "xywz"

client = boto3.client('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,region_name='us-east-1')

ec2_regions = [region['RegionName'] for region in client.describe_regions()['Regions']]

for region in ec2_regions:
  conn = boto3.resource('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,
               region_name=region)
  instances = conn.instances.filter()
  for instance in instances:
    if instance.state["Name"] == "running":
      instancename = ''
      for tag in instance.tags:
        if tag["Key"] == 'Name':
            instancename = tag["Value"]
      print (region, instance.key_name, instance.public_dns_name, instance.image_id, instance.instance_type, instancename)

Answer 2

我们可以使用boto＆＃39;

get_all_instances

可以将标签作为过滤器

参考：http://boto.cloudhackers.com/en/latest/ref/ec2.html

 def list_nodes():
     filter_tags = {
        "tag:Environment": "xyz",
        "tag:Project": "abc",
        "tag:Test": "test",
        "instance-state-name": 'running'
    }
    boto_ec2 = EC2Connection(..)
    reservations = boto_ec2.get_all_instances(filters=filter_tags)
    instances = [i for r in reservations for i in r.instances]
    return instances

使用python按标记名称列出AWS实例

2 个答案: