Question

我有两个List<String>，其中包含

ListOne
          A
          B
          C
ListTwo
          A
          B
          C
          D

现在我需要将移动组合转换为列表字符串

因此输出列表将包含

         A-B
         A-C
         A-D
         B-C
         B-D
         C-D

现在我正在使用Nested for loop。有没有办法使用LINQ或LAMBDA EXPRESSION执行此操作请帮我这样做。提前致谢

示例代码

List<String> ListOne = new List<string> { "A","B","C"};
List<String> ListTwo = new List<string> { "A", "B", "C", "D" };

List<String> Result = new List<string>(from X in ListOne 
                                       from Y in ListTwo 
                                       where X!=Y
                                        select string.Format("{0}-{1}", X, Y));

但它没有给出正确的输出

  It produces like

            A-B
            A-C
            A-D
            B-A
            B-C
            B-D
            C-A
            C-B
            C-D

但是所需的输出就像

         A-B
         A-C
         A-D
         B-C
         B-D
         C-D

使用For Loop

的示例代码

List<String> ResultTwo = new List<string>();
        for (int i = 0; i < ListOne.Count; i++)
        {
            for (int j = 0; j < ListTwo.Count; j++)
            {
                if(ListOne[i] != ListTwo[j])
                    if (ResultTwo.Contains(ListOne[i] + "-" + ListTwo[j]) == false && ResultTwo.Contains(ListTwo[j] + "-" + ListOne[i]) == false) 
                ResultTwo.Add(ListOne[i] + "-" + ListTwo[j]);
            }
        }

它的工作正常....但我只需要一个简单的方法（使用LINQ）

Answer 1

在您编辑之后，这应该可以解决问题：

List<string> ListOne = new List<string>(){"A","B","C"};
List<string> ListTwo = new List<string>(){ "A","B","C","D"};

var result = from a in ListOne
             from b in ListTwo
             let condition = a.CompareTo(b)
             where condition != 0
             select condition < 0 ? a + "-" + b : b + "-" + a;


foreach (var v in result.Distinct())
{
    Console.WriteLine(v);
}

保留订单的第二个版本（ItemFromList1 - ItemFromList2）：

        var result =
            from o in
                (
                    from a in ListOne
                    from b in ListTwo
                    let condition = a.CompareTo(b)
                    where condition != 0
                    select new { a, b, condition }
                )
                group o by
                    o.condition < 0 ? o.a + "-" + o.b : o.b + "-" + o.a into g
                select g.Select(n => n.a + "-" + n.b).Take(1).ToArray()[0];

Answer 2

所以你想要除

之外的所有比赛

与自身匹配的项目
项目与较小的项目匹配

并且没有重复。

这是：

IEnumerable<string> result = 
  (
    from a in ListOne
    from b in ListTwo
    where a != b
    select a.CompareTo(b) < 0 ? a + "-" + b : b + "-" + a
  ).Distinct();

说明要求是战斗的90％。

如果您需要配对中的第一项来自第一个列表，则可以执行此操作：

IEnumerable<string> result = 
  (
    from a in ListOne
    from b in ListTwo
    select new
    {
      A = a,
      B = b,
      Combo = a.CompareTo(b) < 0 ? a + "-" + b : b + "-" + a
    } into x
    group x by x.Combo into g
    select g.Select(x2 => x2.A + "-" + x2.B).First()
  )

Answer 3

var listA = new List<string> { "A", "B", "C" };
var listB = new List<string> { "A", "B" };
var result = listA.SelectMany((a, indexA) =>
                     listB.Where((b, indexB) => 
                            listB.Contains(a) ? !b.Equals(a)&&indexB > indexA 
                                              : !b.Equals(a))
                          .Select(b => string.Format("{0}-{1}", a, b)));

Answer 4

如何将验证逻辑添加到列表中

class Program
{
    static void Main(string[] args)
    {
        List<string> a = new List<string>() { "C", "D", "L" };
        List<string> b = new List<string>() { "C", "L", "C", "D" };

        var pairValuesNotEqual = from vara in a
                from varb in b
                where vara != varb
                select new Pair(vara, varb);


        Set sets = new Set();
        sets.AddRange(pairValuesNotEqual);

        foreach (var item in sets)
        {
            Console.WriteLine(item.First + " - " + item.Second);
        }

        Console.ReadLine();
    }
}

public class Set : List<Pair>
{
    public new void AddRange(IEnumerable<Pair> pairs)
    {
        foreach (var item in pairs)
        {
            this.Add(item);
        }
    }

    public new void Add(Pair item)
    {
        if (!IsExists(item))
            base.Add(item);
    }

    private bool IsExists(Pair item)
    {
        foreach (Pair i in this)
        {
            if (i.First == item.Second && i.Second == item.First)
                return true;
        }

        return false;
    }
}

Answer 5

我不认为LINQ对此有好处，我得到了这个，但它看起来并不好看：

        var A = from one in ListOne
                from two in ListTwo
                where one != two
                let x = one.CompareTo(two) < 0 ? one : two
                let y = one.CompareTo(two) < 0 ? two : one
                select new { X = x, Y = y};

        var B = A.Distinct().Select(a => a.X + "-" + a.Y);

Acualy，当我清理你的嵌套foreach代码时，我比LINQ更喜欢它：

        List<string> outList = new List<string>();
        foreach (string s1 in ListOne)
        {
            foreach (string s2 in ListTwo)
            {
                if (s1 != s2 &&
                    !outList.Contains(s1 + "-" + s2) &&
                    !outList.Contains(s2 + "-" + s1))
                {
                    outList.Add(s1 + "-" + s2);
                }
            }
        }

如何从C＃中的两个List <string>获取移动组合？</string>

5 个答案: