Question

我是Swift中的新手，我希望将我的结构转换为参数，以便用Alamofire 4发布它。请原谅我的英语不好。

我的结构在另一个类中：

import Foundation

class structUser：NSObject {

var myStructUser = [person]()


struct person {
    var firstName : String
    var lastName : String
    var age: Int
    init ( firstName : String, lastName : String, age : Int) {
        self.firstName = firstName
        self.lastName = lastName
        self.age = age

    }
}

override init(){
    myStructUser.append(person(firstName: "John", lastName: "Doe", age: 11))
    myStructUser.append(person(firstName: "Richard", lastName: "Brauer", age : 22))
    myStructUser.append(person(firstName: "Merrideth", lastName: "Lind", age : 55))
}

}

现在在Main Class中我想发布Alamofire，但是如何只转换结构中的名字和年龄？

import UIKit

类ViewController：UIViewController {

let classStructUser = structUser()

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.
    print(classStructUser.myStructUser)
}


func postJson(){
    //need format [String : Any]
    for item in classStructUser.myStructUser{
        // var name = classStructUser.myStructUser.name
        // var age = classStructUser.myStructUser.age

    }

  print(classStructUser.myStructUser)

    /*here i need the Json in format:

    {
    "name":"John",
    "age":11
     }

     {
     "name":"Richard",
     "age":22
     }

     {
     "name":"Merrideth",
     "age":55
     }


     an so on array.count
     */
}

}

另一个问题：

如何从VieControllerClass

访问struct（structUser）中的变量谢谢你的帮助！请解释完整的解决方案，因为我想了解它是如何工作的。 THX！

Answer 1

class structUser: NSObject{

    var myStructUser = [person]()

    struct person {
        var firstName : String
        var lastName : String
        var age: Int
        init ( firstName : String, lastName : String, age : Int) {
            self.firstName = firstName
            self.lastName = lastName
            self.age = age

        }

        static func jsonArray(array : [person]) -> String
        {
            return "[" + array.map {$0.jsonRepresentation}.joined(separator: ",") + "]"
        }

        var jsonRepresentation : String {
            return "{\"name\":\"\(firstName)\",\"age\":\"\(age)\"}"
        }
    }

    func jsonRepresentation() -> String {
        return person.jsonArray(array: myStructUser)
    }

    override init(){
        myStructUser.append(person(firstName: "John", lastName: "Doe", age: 11))
        myStructUser.append(person(firstName: "Richard", lastName: "Brauer", age : 22))
        myStructUser.append(person(firstName: "Merrideth", lastName: "Lind", age : 55))
    }
}

并像这样使用它。

let jsonString = classStructUser.myStructUser.jsonRepresentation()

Swift 3结构为Alamofire4的参数

1 个答案: