Question

我的输入json如下所示，

{"contents":[{"type":"field"},{"type":"field","itemId":"594b9980e52b5b0768afc4e8"}]}

条件是，如果类型是'field'，那么'itemId'应该是必填字段如果类型是'fieldGroup'或'subSection'，那么'itemId'是可选的

这是我试过的Json Schema，它没有按预期工作，

"type": "object",
"additionalProperties": false,
"properties" : {
    "contents" : {
        "type" : "array",
        "items": {"$ref": "#displayItem" }
    }
},
"definitions": {
    "displayItem" : {
        "id": "#displayItem",
        "type": "object",
        "items": {
            "anyOf": [
                {"$ref": "#fieldType"},
                {"$ref": "#fieldGroupSubSectionType"}
            ]
        }
    },

    "fieldType" : {

        "id": "#fieldType",
        "type": "object",
        "additionalProperties": false,
        "properties": {
            "itemId": {
                "type": "string"
            },
            "type": {
                "type": "string",
                "enum": ["field"]
            }
        }

    },

    "fieldGroupSubSectionType" : {

        "id": "#fieldGroupSubSectionType",
        "type": "object",
        "additionalProperties": false,
        "properties": {
            "itemId": {
                "type": [ "string", "null" ]
            },
            "type": {
                "type": "string",
                "enum": [
                    "fieldGroup",
                    "subSection"
                ]
            }
        }

    }
}

感谢使用Sample Json Schema实现上述用例的任何帮助/解决方法。

Answer 1

如果我理解你想要的描述，那么你提供的json示例是无效的，因为它有一个类型：“field”但没有“itemId”属性。

假设这是真的。而不是使用

键入：[“string”，null]

使用必需属性。

我稍微改变了你的模式，而不是单独定义我内联它们，但除此之外（和使用必需的）是相同的：

{
  "type": "object",
  "additionalProperties": false,
  "properties": {
    "contents": {
      "type": "array",
      "items": {
        "anyOf": [
          {
            "type": "object",
            "additionalProperties": false,
            "properties": {
              "itemId": {
                "type": "string"
              },
              "type": {
                "type": "string",
                "enum": [
                  "field"
                ]
              }
            },
            "required": [
              "itemId"
            ]
          },
          {
            "type": "object",
            "additionalProperties": false,
            "properties": {
              "itemId": {
                "type": "string"
              },
              "type": {
                "type": "string",
                "enum": [
                  "fieldGroup",
                  "subSection"
                ]
              }
            }
          }
        ]
      }
    }
  }
}

Answer 2

这是您的最佳实践和风格的清理答案。诀窍是你需要使用暗示＆＃34; a暗示b＆lt; =＆gt; （不是a）或b＆＃34;。在这种情况下，你有＆＃34; type = field意味着itemId是必需的＆lt; =＆gt; type不是field或itemId是必需的＆＃34;。

{
  "type": "object",
  "properties": {
    "contents": {
      "type": "array",
      "items": { "$ref": "#/definitions/displayItem" }
    }
  },
  "definitions": {
    "displayItem": {
      "type": "object",
      "properties": {
        "itemId": { "type": "string" },
        "type": { "enum": ["field", "fieldGroup", "subSection"] }
      },
      "anyOf": [
        { "not": { "$ref": "#/definitions/fieldType" } },
        { "required": ["itemId"] }
      ]
    },
    "fieldType": {
      "properties": {
        "type": { "enum": ["field"] }
      }
    }
  }
}

AJV架构验证错误

2 个答案: