Question

在我的应用程序中，我需要在单个查询中执行多个select语句。我正在使用node-querybuilder

https://www.npmjs.com/package/node-querybuilder

我正在使用.query方法执行自定义查询（不生成查询）这是代码

    user.earning_information = function(key){
    return new Promise(function(resolve,reject){
        let balance = user.userData.balance;
        let query = "SELECT SUM(`amount`) as `total_earnings` FROM `earnings` WHERE `tid` = "+key+";";
            query += "SELECT SUM(`amount`) as `total_earnings_ref` FROM `earnings` WHERE `tid` = "+key+" AND `type` LIKE 'ref%';";
            query += "SELECT SUM(`amount`) as `total_earnings_ref1` FROM `earnings` WHERE `tid` = "+key+" AND `type` = 'ref';";
            query += "SELECT SUM(`amount`) as `total_earnings_ref2` FROM `earnings` WHERE `tid` = "+key+" AND `type` = 'ref_pa';";
            query += "SELECT SUM(`amount`) as `total_earnings_ref3` FROM `earnings` WHERE `tid` = "+key+" AND `type` = 'ref_supa';";
            query += "SELECT SUM(`amount`) as `total_earnings_invest` FROM `earnings` WHERE `tid` = "+key+" AND `type` = 'invest';";
        console.log(query);
        dbc.db_query(query).then(function(data){            
            console.log(data);
        }).catch(function(err){
            console.log(err);
        });
    });
}

我已经将查询记录到控制台了，这就是我得到的，我甚至在phpmyadmin上运行它并且它可以工作并返回数据。

SELECT SUM（amount）as total_earnings FROM earnings WHERE tid = 157632672; SELECT SUM（amount）as total_earnings_ref FROM { {1}} WHERE earnings = 157632672 AND tid LIKE'ref％'; SELECT SUM（type）为amount FROM total_earnings_ref1 WHERE {{1} } = 157632672 AND earnings ='ref'; SELECT SUM（tid）为type FROM amount WHERE total_earnings_ref2 = 157632672 AND earnings = 'ref_pa'; SELECT SUM（tid）as type FROM amount WHERE total_earnings_ref3 = 157632672 AND earnings ='ref_supa'; SELECT SUM（{{1 } {} tid FROM type WHERE amount = 157632672 AND total_earnings_invest ='invest';

但是，当我以编程方式运行它时，会抛出此错误。

earnings

知道为什么会这样吗？顺便说一下，数据库是mySQL，错误是MariaDB。

nodeJS中的多语句查询抛出错误

0 个答案: