Question

我使用的是xampp，我的文件位于xampp / htdocs / Project中。我认为php代码出现在网站上，因为我在浏览器中调用它的方式：http://localhost:8081/login.php但我不确定是不是问题。

我的login.php就是这样：http://imgur.com/a/nCpI1

Login.php代码：

<!DOCTYPE html>
<html lang="pt-PT">
<head>
    <meta charset="UTF-8">
    <title>LOGIN</title>
    <link rel="stylesheet" type="text/css" href="styles/menu.css">
    <link rel="stylesheet" type="text/css" href="styles/homesheet.css">
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>  
<link href="https://fonts.googleapis.com/css?family=Fira+Sans+Condensed" rel="stylesheet"> 
</head>
<body>

<?php
error_reporting(E_ALL);

session_start();

//Start Database

$con = mysqli_connect("localhost","root","","loja");

// Check connection
if (!$con) {
    echo "<div>";
    echo "Falha ao conectar ao MySQL: " . mysqli_connect_error();
    echo "</div>";
}
if( isset($_SESSION["name"]) && $_SESSION["name"] )
{
    echo "You are already logged in, ".$_SESSION['name']."! <br> I'm Loggin you out M.R ..";
    unset( $_SESSION );
    session_destroy();
    header('Location: login.php');
    exit;
}

$loggedIn = false;

$userName = isset($_POST["name"]) ? $_POST["name"] : null;

$userPass = isset($_POST["pass"]) ? $_POST["pass"] : null;

if ($userName && $userPass )
{
    $query = "SELECT username FROM login WHERE username = '$userName' AND password = '$userPass'";
    $result = mysqli_query( $con, $query);
    $row = mysqli_fetch_array($result);

    if(!$row){
        echo "<div>"
        echo "Dados invalidos.";
        echo "</div>"
    }
    else {
        $loggedIn = true;
    }
}

if ( !$loggedIn )
{
    echo "
            <div style='width:500px;'>  
                <h3>Login</h3>
                <form method='post'>
                    <label>Username</label>
                    <input type='text' name='name' placeholder='Username' value='$userName'/>
                    <label>Password</label>
                    <input type='password' name='pass' placeholder='Password' value='$userPass'/>
                    <button>Login</button>
                </form>
            </div>

            <footer>
                <h4 style="text-align:right;">Copyright &copy; est.setubal.com</h4>
            </footer>
        ";
}
else{
    echo "<div>";
    echo "Iniciou a sessao como: $userName!";
    echo "</div>";
    header('Location: home.html');
    $_SESSION["name"] = $userName;
}
?>
</body>
</html>

session.php文件：

<?php
// Establishing Connection with Server by passing server_name, user_id and password as a parameter
$connection = mysql_connect("localhost", "root", "");

// Selecting Database
$db = mysql_select_db("loja", $connection);
session_start();// Starting Session
// Storing Session
$user_check=$_SESSION['login_user'];
// SQL Query To Fetch Complete Information Of User
$ses_sql=mysql_query("select user from login where user='$user_check'",$connection);
$row = mysql_fetch_assoc($ses_sql);
$login_session =$row['user'];
if(!isset($login_session)){
mysql_close($connection); // Closing Connection
header('Location: main.php'); // Redirecting To Home Page
}
?>

我的桌子＆＃34;登录＆＃34;作为用户名和密码字段。我需要一个新的眼睛，可以告诉我还有什么办法可以使登录正常工作。

Answer 1

看来你的php模块丢失了

您必须在httpd-xampp.conf

中加入httpd.conf

# XAMPP settings
Include "conf/extra/httpd-xampp.conf"

默认设置位于xampp\apache\conf\extra\httpd-xampp.conf

#
# PHP-Module setup
#
LoadFile "F:/xampp/php/php7ts.dll"
LoadFile "F:/xampp/php/libpq.dll"
LoadModule php7_module "F:/xampp/php/php7apache2_4.dll"

<FilesMatch "\.php$">
    SetHandler application/x-httpd-php
</FilesMatch>
<FilesMatch "\.phps$">
    SetHandler application/x-httpd-php-source
</FilesMatch>

#
# PHP-CGI setup
#
#<FilesMatch "\.php$">
#    SetHandler application/x-httpd-php-cgi
#</FilesMatch>
#<IfModule actions_module>
#    Action application/x-httpd-php-cgi "/php-cgi/php-cgi.exe"
#</IfModule>


<IfModule php7_module>
    PHPINIDir "F:/xampp/php"
</IfModule>

<IfModule mime_module>
    AddType text/html .php .phps
</IfModule>

ScriptAlias /php-cgi/ "F:/xampp/php/"
<Directory "F:/xampp/php">
    AllowOverride None
    Options None
    Require all denied
    <Files "php-cgi.exe">
          Require all granted
    </Files>
</Directory>

<Directory "F:/xampp/cgi-bin">
    <FilesMatch "\.php$">
        SetHandler cgi-script
    </FilesMatch>
    <FilesMatch "\.phps$">
        SetHandler None
    </FilesMatch>
</Directory>

Answer 2

我猜你通过XAMPP启动了Apache服务...... 您的代码看起来没问题...尝试键入http://localhost/login.php而不是8081 ...它可能会解决您的问题！否则，如果它搞砸了，请查找httpd.conf文件（xampp app config-> httpd.conf）！

登录页面显示php代码和下一步

2 个答案: