Question

我目前正在尝试汇总一些数据，以便日后导出到1条记录，其中每条记录的LookUpID是相同的

application_id  card_holder_name  transaction_id   LookUpID
1060693         Bob               6247460          765858xxxxxx9999_2017
964851          James             6259094          765858xxxxxx9999_2017
937321          Fred              6262332          765858xxxxxx9999_2017

在这种情况下，应该有一条记录，但应该汇总application_id，card_holder_name，transaction_id的数据。每个元素将由回车符分隔，但仍然相互关联。

E.G。

LookUpID               Application_ID        Card_Holder_Name Transaction_ID
765858xxxxxx9999_2017  1060693 964851 937321 Bob James Fred   6247460 6259094 6262332

下面的代码在查看application_id时工作正常，但在添加card_holder_name和tranaction_id时，它们不是彼此属于的代码。我没想到它会像复制代码一样容易，这正是我最初的做法。任何人都可以帮忙，代码如下所示。

create table #test (application_id int, card_holder_name varchar(50), transaction_id int, LookUpID nvarchar(50))
insert into #test (application_id, card_holder_name, transaction_id, LookUpID)
select 1060693,         'Bob',               6247460,       '765858xxxxxx9999_2017'
union all
select 964851,          'James',             6259094,          '765858xxxxxx9999_2017'
union all
select 937321,          'Fred',              6262332,         '765858xxxxxx9999_2017'

select LookUpID,
  stuff((SELECT distinct CHAR(13)+CHAR(10) + cast(application_id as varchar(10))
       FROM #test t2
       where t2.LookUpID = t1.LookUpID 
       FOR XML PATH(''), TYPE).value('.','nvarchar(max)'),1,2,'') as Application_ID,
 stuff((SELECT distinct CHAR(13)+CHAR(10) + cast(transaction_id as varchar(10))
       FROM #test t2
       where t2.LookUpID = t1.LookUpID
       FOR XML PATH(''), TYPE).value('.','nvarchar(max)'),1,2,'') as Transaction_ID,
  stuff((SELECT distinct CHAR(13)+CHAR(10) + cast(card_holder_name as varchar(10))
       FROM #test t2
       where t2.LookUpID = t1.LookUpID 
       FOR XML PATH(''), TYPE).value('.','nvarchar(max)'),1,2,'') as Card_Holder_Name
  from #test t1 where LookUpID = '765858xxxxxx9999_2017'
group by LookUpID

我得到的结果是

LookUpID              Application_ID        Transaction_ID   Card_Holder_Name       
765858xxxxxx9999_2017 1060693 937231 964851 6247460 6259094 6262332 Bob Fred James

由于

Answer 1

这里有一点信念，但如果你的意思是你希望每个列的连接值的顺序相同，则需要在每种情况下添加一个显式的ORDER BY子句。但是，您需要删除DISTINCT才能执行此操作，因为您无法GROUP BY一列和ORDER BY另一列（按列值的顺序可能存在于多个组中，因此订单无法维护）。所以你的查询需要是：

create table #test (application_id int, card_holder_name varchar(50), transaction_id int, LookUpID nvarchar(50))
insert into #test (application_id, card_holder_name, transaction_id, LookUpID)
select 1060693,         'Bob',               6247460,       '765858xxxxxx9999_2017'
union all
select 964851,          'James',             6259094,          '765858xxxxxx9999_2017'
union all
select 937321,          'Fred',              6262332,         '765858xxxxxx9999_2017'
union all
select 937320,          'Pete',              600,         '765858xxxxxx9998_2017'
union all
select 937322,          'Darren',              601,         '765858xxxxxx9998_2017'

select LookUpID,
stuff((SELECT CHAR(13)+CHAR(10) + cast(application_id as varchar(10))
   FROM #test t2
   where t2.LookUpID = t1.LookUpID
   order by application_id 
   FOR XML PATH(''), TYPE).value('.','nvarchar(max)'),1,2,'') as Application_ID,
stuff((SELECT CHAR(13)+CHAR(10) + cast(transaction_id as varchar(10))
   FROM #test t2
   where t2.LookUpID = t1.LookUpID
   order by application_id
   FOR XML PATH(''), TYPE).value('.','nvarchar(max)'),1,2,'') as Transaction_ID,
stuff((SELECT CHAR(13)+CHAR(10) + cast(card_holder_name as varchar(10))
   FROM #test t2
   where t2.LookUpID = t1.LookUpID 
   order by application_id
   FOR XML PATH(''), TYPE).value('.','nvarchar(max)'),1,2,'') as Card_Holder_Name
from #test t1 
group by LookUpID

TSQL汇总不会互相引用

1 个答案: