Question

我在字符串中有数字。我想通过循环或任何方式剪切并保持数组然后再将这个数组循环到最低到最高等级。如何获得与我构建的这些数组相同的结果。谢谢。

public class Main
{
    static String input = "1,3,7,11,5,16,13,12,22,14";
    public static void main(String[] args)
    {
       /*
        int[] keep = new int[11]; //How I can know if I don't know total index in first time.`enter code here`
        keep[0] = 1;
        keep[1] = 3;
        keep[2] = 7;
        keep[3] = 11;
        keep[4] = 5;
        keep[5] = 16;
        keep[6] = 13;
        keep[7] = 12;
        keep[8] = 22;
        keep[9] = 14;

        int[] rank = new int[keep.length];
        rank[0] = 1;
        rank[1] = 3;
        rank[2] = 5;
        rank[3] = 7;
        rank[4] = 11;
        rank[5] = 12;
        rank[6] = 13;
        rank[7] = 14;
        rank[8] = 16;
        rank[9] = 22;
        */

        for (int i=0;i<rank.length;i++)
        {
            System.out.println(rank[i]);
        }

    }

}

Answer 1

您需要在输入字符串上使用split方法，然后从String转换为integer

String[] splitted=input.split(",");

int[] keep = new int[splitted.length];

for(int i=0;i<splitted.length;i++){
    keep[i]= Integer.parseInt(splitted[i]);
}

Answer 2

你可以：

将字符串拆分为冒号
流生成的数组
将其映射到整数解析数组中的每个元素
将结果转换为数组

基本上是这样的：

String input = "1,3,7,11,5,16,13,12,22,14";
int[] foo = Stream.of(input.split(",")).mapToInt(Integer::parseInt).toArray();

System.out.println(Arrays.toString(foo));

Answer 3

你可以这样做。

having

如何从字符串到子字符串获取数字并保留在数组中？

3 个答案: