我创建了一个下拉列表,它有超过25个链接下拉列表显示,所以 我需要在dopdown列表中只显示3个(不禁用其他列表),并对所有人执行搜索选项。请帮我找一个解决方案
<div class="dropdown">
<input onclick="myFunction()" class="dropbtn" id="myInput"
onkeyup="filterFunction()">
<div id="myDropdown" class="dropdown-content">
<a href="#about">About</a>
<a href="#base">Base</a>
<a href="#blog">Blog</a>
<a href="#contact">Contact</a>
<a href="#custom">Custom</a>
<a href="#support">Support</a>
<a href="#tools">Tools</a>
</div>
</div>
<script>
/* When the user clicks on the button,
toggle between hiding and showing the dropdown content */
function myFunction() {
document.getElementById("myDropdown").classList.toggle("show");
}
function filterFunction() {
var input, filter, ul, li, a, i;
input = document.getElementById("myInput");
filter = input.value.toUpperCase();
div = document.getElementById("myDropdown");
a = div.getElementsByTagName("a");
for (i = 0; i < a.length; i++) {
if (a[i].innerHTML.toUpperCase().indexOf(filter) > -1) {
a[i].style.display = "";
} else {
a[i].style.display = "none";
}
}
}
</script>
css文件
.dropbtn {
background-color:#E8E0DE;
color: white;
padding: 6px;
font-size: 16px;
border: none;
cursor: pointer;
}
.dropbtn:hover, .dropbtn:focus {
background-color:#FAF6F5;
}
#myInput {
border-box: box-sizing;
position:relative;
top: 10px;
color:black;
background-position: 1px 2px;
background-repeat: no-repeat;
font-size: 16px;
padding: 5px 350px 10px 15px;
border: none;
}
.dropdown {
position: relative;
display: inline-block;
}
.dropdown-content {
display: none;
position: absolute;
background-color: #f6f6f6;
min-width: 230px;
overflow: auto;
box-shadow: 0px 8px 16px 0px rgba(0,0,0,0.2);
z-index: 1;
}
.dropdown-content a {
color: black;
padding: 12px 16px;
text-decoration: none;
display: block;
}
.dropdown a:hover {background-color: #ddd}
.show {display:block;}
</style>
答案 0 :(得分:0)
您最多只想返回3个您想要添加类似于您的过滤器功能的功能,但在找到3个显示样式设置为“”的项目后,将其余设置为“无”
function limitVisibility() {
let div, a, i;
div = document.getElementById("myDropdown");
a = div.getElementsByTagName("a");
for (i = 0; i < a.length; i++) {
let counter = 0;
if (counter < 3 && a[i].style.display === "" ) {
counter += 1;
} else {
a[i].style.display = "none";
}
}
}
并将其包含在onClick和onkeyup中:
答案 1 :(得分:0)
试试这个:
function filterFunction() {
var input, value, filter, ul, li, a, i, limit, init;
input = document.getElementById("myInput");
value = document.getElementById("myInput").value; // ADD INPUT VALUE
filter = input.value.toUpperCase();
div = document.getElementById("myDropdown");
a = div.getElementsByTagName("a");
init = 0;
limit = 3;
for (i = 0; i < a.length; i++) {
if( (a[i].innerHTML.toUpperCase().indexOf(filter) > -1) ) {
if (init < limit) // LIMIT to FIRST 3 results
{
a[i].style.display = "";
}
else if(value =='') // Case when Input is Empty
{
a[i].style.display = "";
}
else
{
a[i].style.display = "none";
}
init++; // counting results
}
else
{
a[i].style.display = "none";
}
}
}