我正在建立一个系统,以.txt格式对一些.log文件进行排序,以便我以后可以将它发送到excel。有70多个文件,并且在每个文件中我都在扫描一个关键字,我得到1000多个字符串,我想在.txt中保存。我可以获取我想要的每个字符串,并查看每个日志已经从哪个.log文件中获取,但现在我想重命名.log来自的文件,其中包含相应的数字1,2,3,4,5 .. 。(每个文件的一个数字,而不是其文件名)。代码:
import glob
def LogFile(filename, tester):
message = []
data = []
print(filename)
with open(filename) as filesearch: # open search file
filesearch = filesearch.readlines() # read file
i = 1
d = {}
for filename in filename:
if not d.get(filename, False):
d[filename] = i
i += 1
for line in filesearch:
if tester in line: # extract ""
start = '-> '
end = ':\ '
number = line[line.find(start)+3: line.find(end)] #[ord('-> '):ord(' :\ ')]
data.append(number) # store all found wors in array
text = line[line.find(end)+3:]
message.append(text)
with open('Msg.txt', 'a') as handler: # create .txt file
for i in range(len(data)):
handler.write(f"{i}|{data[i]}|{message[i]}")
# open with 'w' to "reset" the file.
with open('Msg.txt', 'w') as file_handler:
pass
# ---------------------------------------------------------------------------------
for filename in glob.glob(r'C:\Users\FKAISER\Desktop\AccessSPA\SPA\*.log'):
LogFile(filename, 'Sending Request: Tester')
我尝试过使用此功能
i = 1
d = {}
for filename in filename:
if not d.get(filename, False):
d[filename] = i
i += 1
但它看起来像这样
我希望每个文件的编号与图片中的编号相同,1表示所有26个日志,2表示该文件夹中的10个文件...等等