Question

我想使用python 2.X

将字符串转换为二进制数

Input :  str = "4000ff11941859f3138e00000000673ac3b40047c0762b47818 ......"

     print type(str)
     >> <type 'str'>

输出应为：0100000000001111000100011001010000011000101 .......

     eg: 4 as 0100 
         f as 1111

有人可以建议怎么做吗？提前致谢。

Answer 1

我会这样做：

str = '4000ff11941859f3138e00000000673ac3b40047c0762b47818'
print(bin(int(str, 16)))

Output:
    01000000000000001111111100010001100101000001100001011001111100110001001110001110000000000000000000000000000000000110011100111010110000111011010000000000010001111100000001110110001010110100011110000001100

Answer 2

这是一个代码示例。

您不应将str用作变量名称，它将覆盖内置的str()函数。你需要注意二进制表示的长度。

data = "a1ef4"
new_data=""

base = 16

# look at all characters in the string
for char in data:

    # convert to integer
    number = int(char, base)

    # convert to binary and then to string
    # the string has variable length
    # 4 becomes 100, not 0100
    binary = bin(number)
    binary_string = str(binary)

    # convert to string with fixed length
    binary_string = '{0:04b}'.format(number)

    # append to output data
    new_data += binary_string

# newdata == "10100001111011110100"

Python中的二进制转换

2 个答案: