使用distinct

Question

如何从上表中获得9,300？我只需要添加6500 + 1800 + 1000

这是我当前的查询

SELECT 
SUM(e.amount) / (SELECT count(e2.receipt_no) 
                 FROM entries e2 
                 WHERE e2.receipt_no = e.receipt_no) as total,
e.user_id
FROM
entries e
GROUP BY e.receipt_no

结果是

现在我需要获得每user_id

的总数

预期输出应为

Answer 1

根据我的理解，这应该让你想要你想要

SELECT sum(DISTINCT amount) as total, reciept_no FROM entries GROUP BY receipt_no

Answer 2

尝试这样的事情

SELECT SUM(DISTINCT(amount)) as total, user_id FROM `entries` GROUP BY user_id

Answer 3

试试这个

 SELECT SUM(amount) as total,user_id FROM entries GROUP BY user_id 

Answer 4

首先按userid，receipt_no计算DISTINCT金额组，然后按user_id计算条目组的总和：

SELECT sum(total),userid from (SELECT sum(DISTINCT amount) as total, 
userid,receipt_no FROM entries GROUP BY userid,receipt_no) as rgrouped 
GROUP BY userid

Answer 5

你也可以尝试这个

SELECT  user_id, SUM(DISTINCT `amount`) FROM `test` group by `user_id`

第1步：为每个用户ID选择不同的金额

101 -  6500,1800,1000 
189 - 1019.00

步骤2

101 = 6500+1800+1000 = 9300.00
189 = 1019.00

这将为每个用户ID选择distinct金额，然后添加所选金额并为您提供相同的结果。