Question

我有一个DataGrid，我设置ItemsSource是ObservableCollection<Dictionary<String, object>>个对象。

通常，我只定义一个ClassA并将ObservableCollection<ClassA>设置为ItemsSource，然后我可以将属性名称绑定到ClassA的列（DataGridTextColumn）。

但我不知道如何绑定词典的键/值。

有任何支持吗？

Answer 1

你要问的是相当复杂的，为了创建ObservableDictionary<TKey, TValue>，你应该创建一个实现的类：

IDictionary
INotifyCollectionChanged
INotifyPropertyChanged 
ICollection<KeyValuePair<TKey,TValue>>
IEnumerable<KeyValuePair<TKey,TValue>>
IEnumerable

接口。 More in depth在这里。这种实施的一个例子是：

class ObservableDictionary<TKey, TValue> : IDictionary, INotifyCollectionChanged, INotifyPropertyChanged
{
    private Dictionary<TKey, TValue> mDictionary;

    //Methods & Properties for IDictionary implementation would defer to mDictionary:
    public void Add(TKey key, TValue value)
    {
        mDictionary.Add(key, value);
        OnCollectionChanged(NotifyCollectionChangedEventArgs(NotifyCollectionChangedAction.Add, value)
        return;
    }

    //Implementation of INotifyCollectionChanged:
    public event NotifyCollectionChangedEventHandler CollectionChanged;
    protected void OnCollectionChanged(NotifyCollectionChangedEventArgs args)
    {
        //event fire implementation
    }

    //Implementation of INotifyProperyChanged:
    public event ProperyChangedEventHandler ProperyChanged;
    protected void OnPropertyChanged(PropertyChangedEventArgs args)
    {
        //event fire implementation
    }
}

另一个是可绑定动态字典的nice solution，它将每个字典条目公开为属性。

public sealed class BindableDynamicDictionary : DynamicObject, INotifyPropertyChanged
{
    /// <summary>
    /// The internal dictionary.
    /// </summary>
    private readonly Dictionary<string, object> _dictionary;

    /// <summary>
    /// Creates a new BindableDynamicDictionary with an empty internal dictionary.
    /// </summary>
    public BindableDynamicDictionary()
    {
        _dictionary = new Dictionary<string, object>();
    }

    /// <summary>
    /// Copies the contents of the given dictionary to initilize the internal dictionary.
    /// </summary>
    public BindableDynamicDictionary(IDictionary<string, object> source)
    {
        _dictionary = new Dictionary<string, object>(source);
    }

    /// <summary>
    /// You can still use this as a dictionary.
    /// </summary>
    public object this[string key]
    {
        get { return _dictionary[key]; }
        set
        {
            _dictionary[key] = value;
            RaisePropertyChanged(key);
        }
    }

    /// <summary>
    /// This allows you to get properties dynamically.
    /// </summary>
    public override bool TryGetMember(GetMemberBinder binder, out object result)
    {
        return _dictionary.TryGetValue(binder.Name, out result);
    }

    /// <summary>
    /// This allows you to set properties dynamically.
    /// </summary>
    public override bool TrySetMember(SetMemberBinder binder, object value)
    {
        _dictionary[binder.Name] = value;
        RaisePropertyChanged(binder.Name);
        return true;
    }

    /// <summary>
    /// This is used to list the current dynamic members.
    /// </summary>
    public override IEnumerable<string> GetDynamicMemberNames()
    {
        return _dictionary.Keys;
    }

    public event PropertyChangedEventHandler PropertyChanged;

    private void RaisePropertyChanged(string propertyName)
    {
        var propChange = PropertyChanged;
        if (propChange == null) return;
        propChange(this, new PropertyChangedEventArgs(propertyName));
    }
}

然后你可以像这样使用它：

private void testButton1_Click(object sender, RoutedEventArgs e)
{
    var dd = new BindableDynamicDictionary(); // Creating a dynamic dictionary.
    dd["Age"] = 32; //access like any dictionary

    dynamic person = dd; //or as a dynamic
    person.FirstName = "Alan"; // Adding new dynamic properties. The TrySetMember method is called.
    person.LastName = "Evans";

    //hacky for short example, should have a view model and use datacontext
    var collection = new ObservableCollection<object>();
    collection.Add(person);
    dataGrid1.ItemsSource = collection;
}

Datagrid需要自定义代码来构建列：

XAML：

<DataGrid AutoGenerateColumns="True" Name="dataGrid1" AutoGeneratedColumns="dataGrid1_AutoGeneratedColumns" />

AutoGeneratedColumns事件：

private void dataGrid1_AutoGeneratedColumns(object sender, EventArgs e)
{
    var dg = sender as DataGrid;
    var first = dg.ItemsSource.Cast<object>().FirstOrDefault() as DynamicObject;
    if (first == null) return;
    var names = first.GetDynamicMemberNames();
    foreach(var name in names)
    {
        dg.Columns.Add(new DataGridTextColumn { Header = name, Binding = new Binding(name) });            
    }            
}

使用ObservableCollection <dictionary <string，object =“”>＆gt;作为WPF中的DataGrid Itemsource

1 个答案: