会好得多。
//Array of objects sample
var objects = [{id:1, name:'test1'}, {id:2, name:'test2'}, {id:3, name: 'test3'}, {id:4, name:'test4'}];
var arrayOfKeys = [3,1,4];
//extract object name property if its id property is equivalent to one of arrayOfKeys [3,1]
//var arrayOfKeys = [3,1,4];
//output sample: extractedName=['test3','test1','test4'];
我一直在使用过滤器和地图但没有用,还尝试在地图中嵌套过滤器获取数组数组,内部是单个对象。
答案 0 :(得分:2)
您可以映射对象并重新映射所需的键以获取名称。
var objects = [{ id: 1, name: 'test1' }, { id: 2, name: 'test2' }, { id: 3, name: 'test3' }],
arrayOfKeys = [3, 1],
result = arrayOfKeys.map((map => id => map.get(id).name)(new Map(objects.map(o => [o.id, o]))));
console.log(result);

答案 1 :(得分:0)
我假设您需要将数组编号映射到id
属性?这是代码,您在数组中map
通过数字和find
来处理对象数组中没有此类id
的情况:
var objects = [{id:1, name:'test1'}, {id:2, name:'test2'}, {id:3, name: 'test3'}];
var arrayOfKeys = [3,1];
var res = arrayOfKeys.map(key => {
var found = objects.find(o => o.id == key);
return found ? found.name : false;
})
console.log(res)
答案 2 :(得分:0)
let objects = [{id:1, name:'test1'}, {id:2, name:'test2'}, {id:3, name: 'test3'}, {id:4, name:'test4'}],
arrayOfKeys = [3,1,4];
let result = objects.reduce((res, obj) => { // loop over the array of objects
let index = arrayOfKeys.indexOf(obj.id); // check if the current object's id is in the array of keys
if(index !== -1) { // if it's there
res.push(obj.name); // then add the current object's name to the result array
arrayOfKeys.splice(index, 1); // remove its id from the array of keys so we won't search for it again (optional, slightly better than leaving it there)
}
return res;
}, []);
console.log(result);
答案 3 :(得分:0)
我认为你使用过滤器走在了正确的轨道上。您可以使其可读性和简洁性。
var objects = [{id: 1,name: 'test1'}, {id: 2,name: 'test2'}, {id: 3,name: 'test3'}, {id: 4,name: 'test4'}],
arrayOfKeys = [3, 1, 4];
var result = objects.filter((x, i) => {
if (arrayOfKeys.some(k => x.id === k)) {
return true;
}
})
console.log(result.map(x=>x.name));
更短的东西!会是
var objects = [{id: 1,name: 'test1'}, {id: 2,name: 'test2'}, {id: 3,name: 'test3'}, {id: 4,name: 'test4'}],arrayOfKeys = [3, 1, 4];
var result = objects.filter((x, i) => arrayOfKeys.some(k => x.id === k));
console.log(result.map(x=>x.name));